Answer:
SUMMARY:
→ Not a Polynomial
→ A Polynomial
→ A Polynomial
→ Not a Polynomial
→ A Polynomial
→ Not a Polynomial
Step-by-step explanation:
The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form
.
Here:
= non-negative integer
= is a real number (also the the coefficient of the term).
Lets check whether the Algebraic Expression are polynomials or not.
Given the expression

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains
, so it is not a polynomial.
Also it contains the term
which can be written as
, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression
is not a polynomial.
Given the expression

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.
Given the expression

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!
Given the expression

is not a polynomial because algebraic expression contains a radical in it.
Given the expression

a polynomial with a degree 3. As it does not violate any condition as mentioned above.
Given the expression


Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.
SUMMARY:
→ Not a Polynomial
→ A Polynomial
→ A Polynomial
→ Not a Polynomial
→ A Polynomial
→ Not a Polynomial
1/2 over -2/5 + (-1/4)
10/20 over -8/20 + (-5/20)
1 5/20 + (-5/20)
1
The answer is 1
Answer:
“I think wolves are scary, too. You’ll have to do more to convince me that they’re not!”
Step-by-step explanation:
Answer : C
we need to the value of f(–1)
Table is given in the question
From the table ,
f(x) = 4 when x= -5, that is f(-5) = 4
f(x) = 0 when x= -1, that is f(-1) =0
f(x)= -1 when x=6, that is f(6) = -1
f(x)= -3 when x=9, that is f(9) = -3
So, the value of f(–1) = 0