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34kurt
2 years ago
5

Need this for my teacher

Mathematics
2 answers:
KiRa [710]2 years ago
7 0
Combine then and you will get your answer
ra1l [238]2 years ago
4 0
I believe you combine the first and last terms first because they have the same denominator
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Please help me I’m so lost
Snezhnost [94]

Answer:

You do 26 times 30 and then divide it by 2

3 0
3 years ago
Read 2 more answers
Someone explain this step by step to me 1/2(c-8)=
polet [3.4K]

Answer: c/2-4


Step-by-step explanation:

This is what I get :

1/2(c-8)

Distributed property

1/2(c) + 1/2(-8)


Do c and -8 as a fraction with denominator 1 solve across

1/2×c/1+1/2×-8/1


Here you can only divide -8by 2

C/2-8/2

To get -4

C/2-4


You can't go further

4 0
3 years ago
It takes Andre 4 minutes to swim 5 laps. How many laps per minute is that?
Nadya [2.5K]

Answer:

1/2

Step-by-step explanation:

6 0
3 years ago
Could anyone help me with this question? Thank you!
shutvik [7]

Answer:

C

Step-by-step explanation:

We want to simplify the rational expression:

\displaystyle \frac{n^4-11n^2+30}{n^4-7n^2+10}

First, we can factor both the numerator and the denominator. This yields:

\displaystyle =\frac{(n^2-6)(n^2-5)}{(n^2-2)(n^2-5)}

Cancel like terms:

\displaystyle =\frac{(n^2-6)}{(n^2-2)}

However, since we canceled a term from our expression, we must place restrictions in order to stay true to the original expression.

Rational expressions are undefined whenever the denominator equals 0. The denominator is (before canceling):

(n^2-2)(n^2-5)=0

Solve for n. By the zero product property:

n^2-2=0\text{ and } n^2-5=0

Therefore:

n^2=2\text{ and } n^2=5

By taking the square root of both sides (since we are taking an even root, it is required to have plus/minus):

n=\pm\sqrt{2}\text{ and } n=\pm\sqrt5

Therefore, our fully simplified expression is:

\displaystyle \frac{n^2-6}{n^2-2}\, ,n\neq \pm\sqrt5, \pm\sqrt2

Hence, our answer is C!

4 0
3 years ago
Three consecutive integers add to 567. Find the integers. PLEASE HELP
Aleks04 [339]
Consecutive integers mean one after the other and their difference would one more or less.

Let the numbers be x, x +1, x +2.

Therefore x + (x+1) + (x +2) = 567
               3x + 3 = 567
               3x = 567 -3 = 564
               3x = 564  Divide by 3.
                 x  = 564/3
                 x  = 188
Therefore integers  x, x +1, x +2 = 188, 188+1, 188+2.
                                                =  188, 189, 190.
Cheers.
7 0
3 years ago
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