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3 years ago

Roll 2 six-sided number cubez how many possibilties contain only even numbers

Mathematics

1 answer:

jeka943 years ago

6 0

Answer:

1/2 of the possibilities are even number

Step-by-step explanation:

Add all of the sides together, you get 12, count on even numbers until you get to 12. 2,4,6,8,10,12. that's six numbers which is half of 12. so half of the possibilities are even.

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He daily milk production of guernsey cows is approximately normally distributed with a mean of 35 kg/day and a standard deviatio

soldier1979 [14.2K]

Answer:

25.1 kg

Step-by-step explanation:

A suitable probability calculator can tell you the 5th percentile of this distribution.

7 0

3 years ago

Select all that apply.

Nikolay [14]

Answer:

standard and measure

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2 years ago

What is 1675 divided by 25 with remainder?

attashe74 [19]

Answer:

975

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I don’t understand lol

pogonyaev

Answer:

3*r = 3

Step-by-step explanation:

$\dfrac{24}{r}=3\\\\24 = r*3\\\\\dfrac{24}{3}=r\\\\6 = r$ 6 is a solution.

$3*r=3\\\r =\dfrac{3}{3}\\\\r = 1\\$

6 is not a solution.

$7r = 42\\\\r =\dfrac{42}{7}\\\\r = 6$

6 is a solution

8 0

2 years ago

Read 2 more answers

Solving Rational Inequalities and use sign diagram to sketch the graph. Image attached for better understanding.

Digiron [165]

Answer:

x ∈ (-∞, -1) ∪ (1, ∞)

Step-by-step explanation:

To solve this problem we must factor the expression that is shown in the denominator of the inequality.

So, we have:

$x ^ 2-1 = 0\\x ^ 2 = 1$

So the roots are:

$x = 1\\x = -1$

Therefore we can write the expression in the following way:

$x ^ 2-1 = (x-1)(x + 1)$

Now the expression is as follows:

$\frac{(x-2) ^ 2}{(x-1) (x + 1)}\geq0$

Now we use the study of signs to solve this inequality.

We have 3 roots for the polynomials that make up the expression:

$x = 1\\x = -1\\x = 2$

We know that the first two are not allowed because they make the denominator zero.

Observe the attached image.

Note that:

$(x-1)\geq0$ when $x\geq-1$

$(x + 1)\geq0$ when $x\geq1$

and

$(x-2) ^ 2$ is always $\geq0$

Finally after the study of signs we can reach the conclusion that:

x ∈ (-∞, -1) ∪ (1, 2] ∪ [2, ∞)

This is the same as

x ∈ (-∞, -1) ∪ (1, ∞)

6 0

3 years ago