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2 years ago

6x^2+42x+72=36 solve

Mathematics

1 answer:

pishuonlain [190]2 years ago

8 0

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation and set all terms equal to 0 :

6*x^2+42*x+72-(36)=0

Answer: X= -1, -6

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Graph the circle x^2+y^2+2x+4y-44=0

Natasha_Volkova [10]

Answer:

See explanation

Step-by-step explanation:

First, convert this to standard form. By completing the square, you can do the following:

$(x^2+2x+1)-1+(y^2+4y+4)-4-44=0$

$(x+1)^2+(y+2)^2=49$

This is a circle with center (-1,-2), and radius 7. It looks like the one I graphed below. Hope this helps!

6 0

3 years ago

In a random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand. C

horrorfan [7]

Answer:

90% confidence interval for the proportion of fans who bought food from the concession stand

(0.5603,0.6529)

Step-by-step explanation:

Step(i):-

Given sample size 'n' =300

Given data random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand.

Given sample proportion

$p^{-} = \frac{x}{n} = \frac{182}{300} =0.606$

level of significance = 90% or 0.10

Z₀.₁₀ = 1.645

90% confidence interval for the proportion is determined by

$(p^{-} - Z_{0.10}\sqrt{\frac{p(1-p)}{n} } , p^{-} +Z_{0.10}\sqrt{\frac{p(1-p)}{n} })$

$(0.6066 - 1.645\sqrt{\frac{0.6066(1-0.6066)}{300} } ,0.6066+1.645\sqrt{\frac{0.6066(1-0.6066)}{300} })$

(0.6066 - 0.0463 ,0.6066 + 0.0463)

(0.5603,0.6529)

final answer:-

90% confidence interval for the proportion of fans who bought food from the concession stand

(0.5603,0.6529)

5 0

3 years ago

When playing the roulette at a casino, you have exactly 1/35 chance of winning in each round if you play a single number. Your f

Vikentia [17]

Answer:

0.2275 = 22.75% probability that you actually won that round

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Fireworks going off

Event B: You won

Probability of fireworks going off.

100% of 1/35 = 0.0286(when you win)

10% of 34/35 = 0.9714(you lost). So

$P(A) = 0.0286 + 0.1*0.9714 = 0.12574$

Probability of you winning and fireworks going off:

100% of 1/35, so $P(A \cap B) = 0.0286$

If you failed to see the outcome of a round, but you see the fireworks going off, then what is the probability that you actually won that round?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0286}{0.12574} = 0.2275$

0.2275 = 22.75% probability that you actually won that round

8 0

3 years ago

Find the hcf of 24x3yz4,30x2y2z3 and 36 x3y2z3

dusya [7]

Answer:

8xyz

Step-by-step explanation:

multiply all numbers and alphabets

288xyz, 2.360xyz, 3.648xyz
find HCF of numbers and after multiply by xyz
288={2×2×2×31}
360={2×2×2×3×3×5}
648={2×2×2×3×3×3×3}
HCF={2×2×2}xyz
8xyz

7 0

2 years ago

Im a brainless plus member and the only reason I joined was because it said I would get instant answers. I have been waiting alm

julia-pushkina [17]

What is your question that you’ve been waiting for an answer to? I’ll try to help.

3 0

3 years ago