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Liono4ka [1.6K]
3 years ago
13

Graph the line that passes through the points ( 0 , − 4) and (−5,2) and determine the equation of the line.

Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0
  1. Answer:

i am highly sorry but there is no graph for me to help you with on this site :(

but to help you the X line always comes first for example the (-5,2) the -5 would be on the X line. I really hope that this help. :)

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Which is a composite number<br> 81<br> 61<br> 71<br> 41
Ne4ueva [31]

Answer:

81

Step-by-step explanation:

A composite number has factor more than just one and itself.

Factors of 81=

1, 3, 9, 27, 81

4 0
3 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
3 years ago
Read 2 more answers
Kevin is baking cookies. each batch of cookies uses 1/8 pound of butter. kevin has 1 3/8 pounds of butter. how many batches of c
Ronch [10]
1 3/8 / 1/8=11/8 x 8/1=11 batches.
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3 years ago
Please help asap.<br> no fake answers or links.<br> picture below.
sesenic [268]

Answer:

b is the correct answer. I'm sure ♡

Step-by-step explanation:

- don't mind this I had to edit my answer lol. but I hope I helped u good luck. If I'm wrong someone can correct me below ☆

8 0
3 years ago
Jessica and nancy are members of different video game libraries. jessica pays a membership fee of $40, and she pays $50 for ever
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It would be 10 because With Nancy, y=4x+30, 30 is the membership fee which is 10 less than Jessicas membership fee of 40.

7 0
3 years ago
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