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2 years ago

Jace estimated the product of (34.57)(–0.74) by rounding each number to the nearest tenth. What was Jace’s estimate?

Mathematics

2 answers:

Naddika [18.5K]2 years ago

7 0

The answer is A. -25.6

RUDIKE [14]2 years ago

6 0

Answer:

jaces estimate

Step-by-step explanation:

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sergiy2304 [10]

Answer:

the length would be 12.

Step-by-step explanation:

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3 years ago

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The square root of 9x plus 7 plus the square rot of 2x equall to 7

Oliga [24]

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x=2

4 0

2 years ago

What are the vertices of the hyperbola whose equation is (y+6)^2/81 - (x+8)^2/49 = 1

olchik [2.2K]

Answer:

(-8,3) and (-8, -15)

Step-by-step explanation:

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3 years ago

Please help and please no links or just answering for points ¯\_(ツ)_/¯

Helga [31]

Answer:

8c + 6 = 3

Step-by-step explanation:

six more than the product of a number and 8 is 3

the product of 8 and c is 8•c, which can also be written as 8c. 6 more than that means you are adding 6, and getting 3... so your equation is,

8c + 6 = 3

hope this helped!

mark me brainliest :D

5 0

2 years ago

Is it possible for the function f(x) - 5 x 2^x to have an output of 200?

Advocard [28]

Answer:

The solution is possible

Step-by-step explanation:

Given

$f(x) = 5 * 2^x$

Required

Is an output of 200, possible?

To know if it is possible or not, we start by substituting 200 for f(x)

$200 = 5 * 2^x$

Divide both sides by 5

$\frac{200}{5} = \frac{5}{5} * 2^x$

$\frac{200}{5} = 2^x$

$40 = 2^x$

$2^x =40$

Take logarithm of both sides

$log2^x =log40$

Apply law of logarithm

$xlog2 =log40$

Divide both sides by log2

$x = \frac{log40}{log2}$

$x = \frac{1.6021}{0.3010}$

$x = 5.32$

for f(x) = 200, x is approximately 5.32

Hence, the solution is possible

8 0

2 years ago