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Alex787 [66]
3 years ago
5

I needddd helpppp asappppp

Mathematics
1 answer:
alexgriva [62]3 years ago
7 0

Answer:

Step-by-step explanation:

<u><em>Part A: </em></u>Slope of parallel lines are equal.

4x - 3y - 7 = 0 ⇔ y = \frac{4}{3} x - \frac{7}{3}

m = \frac{4}{3}

y - 3 = \frac{4}{3} ( x + 2 ) ⇔ y = \frac{4}{3} x + \frac{17}{3} ⇔ <em>4x - 3y + 17 = 0</em>

<u><em>Part B: </em></u>Slope of perpendicular lines are opposite reciprocal.

m_{1} × m_{2} = - 1

m_{1} = \frac{4}{3}

m_{2} = - \frac{3}{4}

y - 3 = - \frac{3}{4} ( x + 2 ) ⇔ y = - \frac{3}{4} x + \frac{3}{2} ⇔ <em>3x + 4y - 6 = 0</em>

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I hope that's help.

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Let x represent the measurement of an acute angle in degrees. The ratio of the complement of x to the supplement of c is 2:5. Gu
sergiy2304 [10]

<u>Answer:</u>

The ratio of the complement of x to the supplement of x is 2:5. The value of x is 30

<u>Solution:</u>

It is given that x represents the measurement of an acute angle in degrees.  It is also given that the ratio of the complement of x to the supplement of x is 2:5.  

Since it is given that x is an acute angle it means that it has to be less than 90.

Complement of an angle = 90 - x

Supplement of an angle = 180 - x

In this case it is given that the ratio of the complement of x to the supplement of x is 2:5

So we can write the relation as follows:

\begin{array}{l}{\frac{90-x}{180-x}=\frac{2}{5}} \\\\ {(90-x) \times 5=(180-x) \times 2} \\\\ {450-5 x=360-x) \times 2} \\\\ {450-560=5 x-2 x} \\\\ {90=3 x} \\\\ {x=\frac{90}{3}=30}\end{array}

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Here please help me.
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