The percentage increase in the student's height is 10.52%.
Here we are given that a student's height increases from 1.52m to 1.68m.
Thus, the absolute increase in the student's height will be-
1.68 - 1.52 = 0.16 meters.
Now, we need to find the percentage increase in the student's height.
The formula for calculating percentage increase is given by-
Percentage increase = change in value/ initial value * 100
Here, the change in value is 0.16 meters and the initial value is 1.52 meters.
Thus, percentage increase in height = 0.16 / 1.52 *100
= 1600/ 152
= 400/ 38
= 200/ 19
= 10.52%
Thus, the increase in the student's height is 10.52%.
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The value of the lower class limit of the 3rd class is; 11.0
<h3>What is the lower class Interval?</h3>
The lower class limit is lowest value of that class interval while upper class limit is highest value of that class interval.
Hours Number of Students
0.0–5.4 12
5.5–10.9 16
11.0–16.4 14
16.5–21.9 11
22.0–27.4 6
Now, the third class interval is 11.0–16.4 and from definition of lower class limit, we can say that the lower class limit of the 3rd class is; 11.0
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