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kow [346]
3 years ago
6

Which of the tables represents a function? (Please refer to image)

Mathematics
1 answer:
jenyasd209 [6]3 years ago
8 0

Answer:

It is C

Step-by-step explanation:

Because no functions have 2 numbers that are the same in the x axis or in the input

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M<GFN = 4x+10, m<NFE = 14x + 3, and m<3GFE = 157°. find m<NFE​
pantera1 [17]

Answer:

115

Step-by-step explanation:

set up the equation to find x:

GFN+NFG=GFE

(4x+10)+(14x+3)=157

calculate for x

you'll get x=8

put 8 into NFE

14(8)+3=115

4 0
3 years ago
What is the value of the product (3-2)(3+21)?<br> 5<br> 9 +41<br> 9-41<br> 13
liraira [26]
(3 - 2)(3 + 21) = 9 + 63 - 6 - 42 = 72 - 6 - 42 = 66 - 42 = 24 (I got 24 as my final answer)
8 0
4 years ago
Read 2 more answers
If f(x) = x2 – 1 and g(x) = 2x – 3, what is the domain of (f*g)(x)?
leva [86]

(f.g)(x) =( f(x))(g(x)) \\  = ( {x}^{2}  - 1)(2x - 3) \\  = (x - 1)(x + 1)(2x - 3)
then the domain of (f•g)(x) is {-1, 1, 3/2}
7 0
4 years ago
Read 2 more answers
What is the solution to -3x&lt;9
GaryK [48]
-3x<9. The way to figure this out is to divide by -3 to get x by itself. Remember, when dividing by a negative, you need to flip the inequality sign.
x>-3 is your answer.
I hope this helps!
7 0
3 years ago
What translation was used on ABCD to produce A'B'C'D'?
Mashutka [201]
First of all, we need to know the coordinate of ABCD and A'B'C'D', so the coordinate of ABCD will be:
A(-3,5)
B(-1,2)
C(-2,-1)
D(-5,-3)
Then, coordinate of new figure will be:
A'(-7,8)
B'(-5,5)
C'(-6,2)
D'(-9,0)
Next,
Let's try all the translations:
(x,y) to (x+4,y+3)
A(-3,5) to A'(-3+4, 5+3)
A(-3,5) to A'(1,8)
Which is not right because A' need to be (-7,8)
(x,y) to (x-4,y+3)
A(-3,5) to A'(-3-4,5+3)
A(-3,5) to A'(-7,8)
B(-1,2) to B'(-1-4,2+3)
B(-1,2) to B'(-5,5)
C(-2,-1) to C'(-2-4,-1+3)
C(-2,-1) to C'(-6,2)
D(-5,-3) to D'(-5-4,-3+3)
D(-5,-3) to D'(-9,0)
Yay, we found the answer. As a result, (x,y) to (x-4,y+3) is your final answer. Hope it help!
7 0
4 years ago
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