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11111nata11111 [884]
3 years ago
11

A function f has derivatives of all orders for all real numbers, x. Assume f(2) = −3, f ′(2) = 5, f ″(2) = 3 and the third deriv

ative of f at x = 2 is −8. Write the 3rd degree Taylor polynomial for f about x = 2 and use it to approximate f(1.5).
Mathematics
1 answer:
nadezda [96]3 years ago
6 0

The Taylor polynomial would be

T_3(x)=f(2)+f'(2)(x-2)+\dfrac{f''(2)}2(x-2)^2+\dfrac{f'''(2)}6(x-2)^3

T_3(x)=-3+5(x-2)+\dfrac32(x-2)^2-\dfrac43(x-2)^3

Then

f(1.5)\approx T_3(1.5)=-\dfrac{119}{24}\approx-4.96

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The amount y (in grams) of the radioactive isotope fermium-253 remaining after t hours is y=a(0.5)t/72, where a is the initial a
almond37 [142]

Answer:

Per hour decay of the isotope is 0.96%.

Step-by-step explanation:

Amount of radioactive element remaining after t hours is represented by

y=a(0.5)^{\frac{t}{72}}

where a = initial amount

t = duration of decay (in hours)

Amount remaining after 1 hour will be,

y=a(0.5)^{\frac{1}{72} }

y = 0.9904a

So amount of decay in one hour = a - 0.9904a

                                                      = 0.0096a gms

Percentage decay every hour = \frac{\text{Amount of decay}}{\text{Initial amount}}\times 100

                                                  = \frac{0.0096a}{a}\times 100

                                                  = 0.958 %

                                                  ≈ 0.96 %

Therefore, per hour decay of the radioactive isotope is 0.96%.

7 0
3 years ago
Jimmy has listed the amount of money in his wallet for each of the last ten days. He decides to remove day 7, as that was payday
abruzzese [7]

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Removing the value for day seven will reduce the sum of money as it will be for 9 days only.In finding the mean, you will divide by 9 days to get mean M₂

Mean M₂ < M₁

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