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11111nata11111 [884]
3 years ago
11

A function f has derivatives of all orders for all real numbers, x. Assume f(2) = −3, f ′(2) = 5, f ″(2) = 3 and the third deriv

ative of f at x = 2 is −8. Write the 3rd degree Taylor polynomial for f about x = 2 and use it to approximate f(1.5).
Mathematics
1 answer:
nadezda [96]3 years ago
6 0

The Taylor polynomial would be

T_3(x)=f(2)+f'(2)(x-2)+\dfrac{f''(2)}2(x-2)^2+\dfrac{f'''(2)}6(x-2)^3

T_3(x)=-3+5(x-2)+\dfrac32(x-2)^2-\dfrac43(x-2)^3

Then

f(1.5)\approx T_3(1.5)=-\dfrac{119}{24}\approx-4.96

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Step-by-step explanation:

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Answer:

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Tn = a + d(n - 1)

Where

a represents the first term of the sequence.

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solniwko [45]

Well, the answer would bee 1/10 for a simple reason: the 3 in 7.315 is in the tenth's spot while the 3 in 893.5 is in the ones. a one spot different that can be proven with logic.

4 0
3 years ago
Need help solving this please
Aloiza [94]

Answer:

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2 years ago
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