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A ship is carrying gold bars and silver bars in the ratio 13:17. The ship's load

Using proportions, considering the weight of each bar and the ratio, it is found that the ship is carrying 52 gold bars.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Each bar weighs 5 kg, and the total weight is of 600 kg, hence the number of bars is given by:

n = 600/5 = 120.

The proportion of gold bars is given by:

p = 13/(13 + 17) = 13/30

Hence, out of 120 bars, the number of gold bars is given by:

nG = 120 x 13/30 = 4 x 13 = 52.

More can be learned about proportions at brainly.com/question/24372153

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4 0

1 year ago

Please Help!<br><br><br><br> B belongs to AC D belongs to lineAF

Anvisha [2.4K]

Answer:

x = 27

Step-by-step explanation:

∠ CAD and ∠ EDF are corresponding angles and are congruent, so

∠ CAD = 2x

The sum of the 3 angles in Δ ABD = 180°

sum the angles and equate to 180

72 + 2x + 2x = 180

72 + 4x = 180 ( subtract 72 from both sides )

4x = 108 ( divide both sides by 4 )

x = 27

5 0

3 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

so

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

so

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago

The expression 8³⋅2−¹⁰ is equal to what?<br> ᶠʳᵉᵉ ᵖᵒᶦⁿᵗˢ!! ᵃⁿᵈ ᶜᵘᵗᵉ ᵖᶦᶜᵗᵘʳᵉˢ ♡

ExtremeBDS [4]

The Awnser is 1/2 I think

8 0

3 years ago

Read 2 more answers

The sum of the measures of two complementary angles exceeds the difference of their measure by 86º. Find the measure of each ang

katrin2010 [14]

We will translate the given statement in the problem into
x + y = 90
x - y = 90 - 86 = 4 where x and y are the angles that are complementary. solving simultaneously, x = 47 degreesy = 43 degrees.

4 0

3 years ago