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Gekata [30.6K]
3 years ago
8

Find the solutions to 6x^2- 54x = 0

Mathematics
1 answer:
Nina [5.8K]3 years ago
4 0

Answer:      

A. x = 9

D. x = 0

Step-by-step explanation:

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have            

6x^{2} -54x=0              

so

a=6\\b=-54\\c=0

substitute in the formula

x=\frac{-(-54)(+/-)\sqrt{-54^{2}-4(6)(0)}} {2(6)}

x=\frac{54(+/-)54} {12}

x=\frac{54(+)54} {12}=9              

x=\frac{54(-)54} {12}=0          

therefore

The solutions are x=0 and x=9

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Consider the initial value problem:
Inessa [10]

Answer:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

Step-by-step explanation:

The given initial value problem is;

y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2

Let

u(t)=y(t)----(2)\\v(t)=y'(t)----(3)

Differentiating both sides of equation (1) with respect to t, we obtain:

u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)

Differentiating both sides of equation (2) with respect to t gives:

v'(t)=y''(t)----(6)

From equation (1),

y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)

Putting t=0 into equation (2) yields

u(0)=y(0)\\\implies u(0)=-5

Also putting t=0 into equation (3)

u'(0)=y'(0)\\u'(0)=2

The system of first order equations is:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

3 0
3 years ago
Can someone answer this question for me pls n thanks
allsm [11]

Answer:

Mean: 29.5;    Median: 26;    Modes: 25, 26

Step-by-step explanation:

Add 10+12+25+25+26+26+30+31+33+34+47+55 = 354

Then divide it by 12      354/12 = 29.5

Mode are numbers that appear most often which in this case are 2 numbers, 25 and 26.

8 0
2 years ago
Please help me! I will make you as the best answer
Alexandra [31]

Answer:

40

Step-by-step explanation:

The area of a rectangle is length*width. So, 200=8(1/2x+5). Dividing by 8, 25=1/2x+5. Subtracting 5, 20=1/2x, multiplying by 2, 40=x.

6 0
3 years ago
Whats the sum of the polynomials (2x3 − 5x − 1) + (4x3 + 8x + 3)
Ipatiy [6.2K]

Answer: 23x

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Insert parentheses in the expression 6 + 10 x 2 so that the expression equals (12+1)*2
Lesechka [4]
6 + (10 x 2) = 26 = (12+1)*2
5 0
3 years ago
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