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Yakvenalex [24]
3 years ago
9

O

Mathematics
1 answer:
deff fn [24]3 years ago
4 0

Answer:

B,∠BAC=40°

Step-by-step explanation:

diameter makes 90° on the circumference.

∠CBA=90°

∠ACB+∠CBA+∠BAC=180°

50+90+∠BAC=180

∠BAC=180-140=40°

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Find the area of a parallelogram ABCD with AB =7 m. AD = 20 m and BAD = 62°.
nikklg [1K]

9514 1404 393

Answer:

  123.6 m²

Step-by-step explanation:

The area is given by the formula ...

  A = (AB)(AD)sin(∠A)

  A = (7 m)(20 m)sin(62°) ≈ 123.6 m²

4 0
3 years ago
Do looks matter when is comes to guys​
jenyasd209 [6]

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Please help the following questions
insens350 [35]

Answer:

<em>Option D</em>

Step-by-step explanation:

Assume that these polygons were similar. You could tell that if they were, ABCD ~ EFGH, and is already noted by the answer choices. We can conclude that AB ~ EF, CD ~ GH and so on. To prove that these shapes are similar, we must form a like proportionality among these side;

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As the proportions we formed were to equal to one another,<em> the solution must be option D!</em>

6 0
3 years ago
Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

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\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
4 years ago
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Hitman42 [59]

Answer:

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