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SpyIntel [72]
3 years ago
10

How do I find the arc from a central angle?

Mathematics
2 answers:
Lesechka [4]3 years ago
8 0

Answer:

Divide the central angle in radians by 2 and perform the sine function on it. Divide the chord length by double the result of step 1. This calculation gives you the radius. Multiply the radius by the central angle to get the arc length.

Ber [7]3 years ago
3 0

Answer:

the arc length divided by the radius of the circle.

Step-by-step explanation:

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One end of a ladder 32 feet long is placed 10 feet from the outer wall of a building that stands on the ground level. How far up
ladessa [460]

Answer:

30 ft

Step-by-step explanation:

This is a classic right triangle problem, where the length of the ladder represents the hypotenuse, where the ladder is lengthwise from the building is the base of the triangle, and what we are looking for is the height of the triangle.  Pythagorean's Theorem will help us find this length.

32^2-10^2=y^2 so

1024 - 100 = y^2 and

y = 30.4 so 30 feet

4 0
3 years ago
I REALLY NEED HELP PLEASEEE!!! I'LL GIVE BRAINLIEST! PLEASE HELP!
marishachu [46]

Answer:

I think the answer would be B.

4 0
3 years ago
Pls help need it ASAP
soldier1979 [14.2K]

Answer:

D

Step-by-step explanation:

2x>7

x>7/2

x>3.5

5 0
3 years ago
Read 2 more answers
5p−3p+9+p+3? pls im failingg
Triss [41]

Answer:

3p + 12

Step-by-step explanation:

5p -3p + 9 + p + 3

Move around the parts of the equation

5p -3p + p + 9 + 3

Add positive 9 to positive 3

5p -3p + p + 12

Add positive p to negative 3p

5p -2p + 12

Combine positive 5p and negative 2p together

3p + 12

I Hope That This Helps! :)

7 0
3 years ago
At the beginning of the year, the ratio of juniors to seniors in high school X was 3 to 4. During the year, 10 juniors and twice
Lady bird [3.3K]

Answer: E. 120

The number of seniors were there in high school X at the beginning of the year = 120

Step-by-step explanation:

Given : At the beginning of the year, the ratio of juniors to seniors in high school X was 3 to 4.

Let the number of juniors be 3x and the number of seniors be 4x.

Since , during the year, 10 juniors and twice as many seniors transferred to another high school, while no new students joined high school X.

i.e. Number of juniors at the end of the year = 3x-10

Number of seniors at the end of the yea = 4x-2(10)=4x-20

At the end of the year, the ratio of juniors to seniors was 4 to 5.

\Rightarrow\dfrac{3x-10}{4x-20}=\dfrac{4}{5}

\Rightarrow5(3x-10)=4(4x-20)

\Rightarrow15x-50=16x-80

\Rightarrow16x-15x=80-50

\Rightarrow x=30

The number of seniors were there in high school X at the beginning of the year = 4(30)=120

Hence, the correct answer is E. 120 .

6 0
3 years ago
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