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trasher [3.6K]
3 years ago
11

Will give brainliest and 5 stars if correct. How does Shakespeare manipulate language?

Mathematics
2 answers:
lions [1.4K]3 years ago
7 0

Answer:

Shakespeare uses the language of the characters to achieve this multifaceted quality. Through the use of language (specifically Iago, Othello, and Desdemona), Shakespeare propels the plot, engages the audience, creates dramatic irony, and reveals the characters’ psyches.

pshichka [43]3 years ago
3 0

Answer:

Shakespeare's writings greatly influenced the entire English language. He expanded the scope of English literature by introducing new words and phrases, experimenting with blank verse, and also introducing new poetic and grammatical structures.

hope this helps

have a good day :)

Step-by-step explanation:

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What is the end behavior in the function y=2x^3-x
sasho [114]

Answer:

Step-by-step explanation:

When a question asks for the "end behavior" of a function, they just want to know what happens if you trace the direction the function heads in for super low and super high values of x. In other words, they want to know what the graph is looking like as x heads for both positive and negative infinity. This might be sort of hard to visualize, so if you have a graphing utility, use it to double check yourself, but even without a graph, we can answer this question. For any function involving x^3, we know that the "parent graph" looks like the attached image. This is the "basic" look of any x^3 function; however, certain things can change the end behavior. You'll notice that in the attached graph, as x gets really really small, the function goes to negative infinity. As x gets very very big, the function goes to positive infinity.

Now, taking a look at your function, 2x^3 - x, things might change a little. Some things that change the end behavior of a graph include a negative coefficient for x^3, such as -x^3 or -5x^3. This would flip the graph over the y-axis, which would make the end behavior "swap", basically. Your function doesn't have a negative coefficient in front of x^3, so we're okay on that front, and it turns out your function has the same end behavior as the parent function, since no kind of reflection is occurring. I attached the graph of your function as well so you can see it, but what this means is that as x approaches infinity, or as x gets very big, your function also goes to infinity, and as x approaches negative infinity, or as x gets very small, your function goes to negative infinity.

6 0
3 years ago
F(x)=2x-4. F(x)=2x-4 f-1x=_x+_. Complete the inverse function
natita [175]

Answer:

f^{-1}(x) = \frac{1}{2}(x +4)

Step-by-step explanation:

Given

f(x) = 2x - 4

Required

Determine the inverse function

Start by replacing f(x) with y

y = 2x - 4

Swap the positions of y and x

x = 2y - 4

Make y the subject: <em>Add 4 to both sides</em>

x+4 = 2y - 4+4

x+4 = 2y

Make y the subject: <em>Divide through by 2</em>

<em></em>\frac{1}{2}(x + 4) = y<em></em>

<em></em>y = \frac{1}{2}(x + 4)<em></em>

<em></em>

Replace y with f-1(x)

f^{-1}(x) = \frac{1}{2}(x +4)

3 0
3 years ago
Which of the following graphs represents a function?
4vir4ik [10]

Answer: you didnt post graphs to look at

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Is (x-4) a factor of f(x) = x3 - 2x2 + 5x + 1? Use either the remainder theorem or the factor theorem to explain your reasoning.
Virty [35]

Answer:

(x-4) is not a factor of f(x)=x³-2x²+5x+1

Step-by-step explanation:

Uding the remainder theorem,(x-4) is a factor if the remainder is 0

Plug in x=4

(4)³-2(4)²+5(4)+1

64-32+20+1

64-53

11

7 0
3 years ago
PLS I NEED HELP NOW PRONTO!!!!!
weeeeeb [17]

Answer:

The mean for Stem is 2.5

The mean for Leaf is 81.25

8 0
2 years ago
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