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JulijaS [17]
3 years ago
5

A must-have for any thrill seeker is a drop tower ride. The Precipice Plummet will stand 420 feet tall. The scale in your archit

ectural diagrams is 1":40'. How tall will your drawing of Precipice Plummet be in inches? (do not include units in your answer, just the number
Mathematics
1 answer:
Gwar [14]3 years ago
6 0

The answer is 10.5, but don't put 10.5 if it's just asking for the number and not the unit only put (10)!!!

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Find the equation in standard form , of the line passing through points (2,-3) and (4,2)
Fudgin [204]

The form of linear equation that describes line is:

y=sx+n

First we must calculate the slope.

s=\dfrac{\Delta{y}}{\Delta{x}}=\dfrac{2-(-3)}{4-2}=\dfrac{5}{2}

Now it looks a bit more like this:

y=\dfrac{5}{2}x+n

All we need now is to put in y and x from one point doesn't matter which. I'll pick A.

The equation now looks like this:

-3=\dfrac{5}{2}\cdot2+n

Solve for n.

-3=5+n \\n=-8

And finally write the equation.

f(x)=\dfrac{5}{2}x-8

Hope this helps.

r3t40

7 0
3 years ago
Simon has 160 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of the garden'
Inessa [10]

It is given in the question , that Simon has 160 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of the garden's width w (in meters) is modeled by

A(w) = -w(w-80)
\\
A(w) = -w^2 + 80w

Which represents parabola and the parabola is maximum at its vertex, that is

w = -\frac{b}{2a} = - \frac{80}{2} = 40 meters

Therefore the width is 40 meters and the area is

A(40) = -40(40-80) = -40*-40 = 1600 meter ^2

8 0
3 years ago
Read 2 more answers
Find the percent change from 40 to 45
Scilla [17]
What is the percent increase from 40 to 45?

Answer: 12.5%
4 0
3 years ago
Read 2 more answers
Write the fraction or mixed number as a decimal
Alenkasestr [34]

Answer:

4/10= 0.4

3 1/10= 3.1

7/10= 0.7

6 5/10= 6.5

9/10= 0.9

Step-by-step explanation:

3 0
3 years ago
Can someone please help with this or explain how to do it. I'm not very sure where to begin ToT
larisa86 [58]

Answer:

d. 12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

Step-by-step explanation:

First, we find the greatest common factor of 12x^23y^40z^9 and 10x^78z^5.

We work on the numbers, then on x, then on y, then on z.

We start with the GCF of 12 and 10.

10 = 2 * 5

12 = 2 * 3 * 3

The only factor 10 and 12 have in common is 2, so the GCF of 12 and 10 is 2.

Now we work on x. We have x^23 and x^78.

x^23 has 23 factors of x.

x^78 has 78 factors of x.

Since x^23 and x^78 have both at least 23 factors of x, x^23 is the GCF of x.

Now we work on y.

There is y^40 in one term, but there is no y in the other term. There is no GCF for the y.

Now we work on z. The first term has z^9. the second term has z^5. They both have at least 5 factors of z, so the GCF of z is z^5.

Now we put all the parts of the GCF together, and the GCF of the two terms is

2x^23z^5

We use option d. to factor.

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(___a____ + ____b___)

We already have the GCF outside the parentheses. Now we need to figure out what goes inside the parentheses.

The terms that go in positions a and b are the terms that when multiplied by the GCF give you the original expression.

We now work on position a.

What do you multiply by 2x^23z^5 to get 12x^23y^40z^9?

Answer: 6y^40z^4

Now we have

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + ____b___)

Now we do the same for position b.

What do you multiply by 2x^23z^5 to get 10x^78z^5?

Answer: 5x^55

Now we have

12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

Answer: d. 12x^23y^40z^9 + 10x^78z^5 = 2x^23z^5(6y^40z^4 + 5x^55)

5 0
2 years ago
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