Answer:
child buffet = $16, adult buffet =$23
Step-by-step explanation:
lets assume that child buffets costs, $x
and adult buffets costs $y
2x+4y= $124 .............this is our first equation
x+4y =$108 ................our second equation
<em>2x + 4y = 124</em>
<em>2x = 124 - 4y</em>
<em>x = 62 - 2y ....from first equation</em>
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<em>x+4y =$108</em>
<em>x = 108 -4y ... from second equation</em>
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now we will solve it through simultaneous equations
<em>62 - 2y = 108 -4y</em>
<em>2y = 46</em>
<em>y = $23</em>
<em>if y =$23</em>
<em>then x = 108 - 4(23)</em>
<em>x = $16</em>
Answer:
x=-2 and y = -4
Step-by-step explanation:
3x-2y=2
Solve for x:
3x=2+2y (adding 2y both sides)
x= (2+2y)/3 (dividing both sides by 3)
Now, substitute x in the second equation:
But first, Notice that second equation can be simplified!
5(x-y) =10 (take 5 out since they're common!)
x-y=10/5 (Divide both sides by 5)
x-y=2
Now, substitute!
[(2+2y)/3] -y =2
(2+2y-3y)/3 =2 (Make common denominator)
2+2y-3y = 2times3 (multiply both sides by 3)
2-y = 6 (Simplify!)
-y = 6-2 (Subtract both sides by 2)
y= -4 (Divide negative both sides)
Now, that you know your y value find x:
Remember x was equal to: (2+2y)/3
Simply, substitute y as -4 and solve for x!
x = 2+2(-4) /3
x = 2-8 / 3
x= -6/3
x= -2
Hope this helps!
Mark brainliest if you think I helped! Would really appreciate!
The answer to this question requires a formula. This formula is pie x radius squared x the height of the cylinder. The diameter is 3 feet, so it's radius is 1.5 feet. Square that and you get 2.25 feet. Take this and multiply it by pie. Most teachers simplify it to 3.14, to make it easier. So the value we have right now is 7.065 feet. Finally, we multiply this value by the height of the cylinder. We take 7.065 and multiply it by 10. The answer is 70.65 ft cubed. We are not done yet, because the question wants yards, not feet. So, the answer is 23.55 cubic yards. All I had to do was divide the value by 3 to get yards. I hope this answers your question as it should. Sorry for over explaining.
