Answer:
A unit of measurement is a specific magnitude of a certain quantity that is specified and recognized by convention or legislation and is commonly used as a standard for measuring the same kind of quantity. We would randomly confuse the computations if the unit system was not given to the measurements.
Step-by-step explanation:
Example: If someone wrote 200 as a response to a question on a piece of paper. But You neglected to mention the measuring units. Anyone can mistake it because there are no units written apart from the number (unit less). Complications multiply. It's impossible to say whether it's 200 m or 200 g. 200 milliliters? 200 kilometers, 200 seconds, or 200 meters? It's possible to guess anything. We should always utilize units to be specific about the answer to any problem. This will assist in narrowing down the approach to any challenge and providing a measurable linked quantity regarding the topic in question.
Answer:
sq rt 74 which is approx 8.6
Step-by-step explanation:
use distance formula
Answer:
F(x) and g(x) are not inverse functions.
Step-by-step explanation:
In order to calculate the inverse function of a function, we have to isolate X and after that, we change the variables.
As our function f(x) is a exponentian function, we can apply logarithm with base 10 (log) in both sides in order to isolate X. Remember that log10=1.
![[tex]y=10^{(x+\frac{2}{3}) }\\\\log y=log 10^{(x+\frac{2}{3}) }\\log y = (x+\frac{2}{3}) . log10\\\frac{log Y}{log10} = (x+\frac{2}{3})\\\frac{log Y}{1} = (x+\frac{2}{3})\\log Y-\frac{2}{3}=x](https://tex.z-dn.net/?f=%5Btex%5Dy%3D10%5E%7B%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%20%7D%5C%5C%5C%5Clog%20y%3Dlog%2010%5E%7B%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%20%7D%5C%5Clog%20y%20%3D%20%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%20.%20log10%5C%5C%5Cfrac%7Blog%20Y%7D%7Blog10%7D%20%3D%20%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%5C%5C%5Cfrac%7Blog%20Y%7D%7B1%7D%20%3D%20%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%5C%5Clog%20Y-%5Cfrac%7B2%7D%7B3%7D%3Dx)
[/tex]
Now we change the variables.
F(x) and g(x) are not inverse functions.
If your functions are
f(x) = 16·x
g(x) = 16·(1/2x)
The output values of g(x) are one-half the output values of f(x) for the same value of x.
If your functions are
f(x) = 16^x
g(x) = 16^(1/2x)
The output vaules of g(x) are the square root of the output values of f(x) for the same value of x.
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You seem to have left out the relevant operator symbol, so we don't really know your intent. Copy/paste operations will do that. Editing is sometimes needed.
