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DerKrebs [107]
3 years ago
6

Which of the following is the primary medium for beach erosion?

Chemistry
1 answer:
Rus_ich [418]3 years ago
3 0

Answer:

Water is the primary erosion

hope it helps :)

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You transfer a sample of a gas at 17°C from a volume of 5.67 L and 1.10 atm to a container at 37°C that has a pressure of 1.10 a
laila [671]

Explanation:

V1T1 = V2T2

V2=V1T1/T2

= 5.67*17/37= 2.6

5 0
4 years ago
What property do all of the group 18 elements have that make them stand out from other elements?
matrenka [14]
They are very stable (not reactive).

This is because their outer shell has a total of 8 valence electrons. All elements strive to get towards a full outer shell, but since these elements already have a full outer shell, they are fairly unreactive.
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3 years ago
Arrange the following which is most reactive to the least reactive when these react in water:
Reika [66]

Answer:

Explanation:

potassium

sodium

lithium

3 0
4 years ago
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Q1. Give the name of one metal and where it is used in the Media sector and give a reason why it is suitable for that particular
Degger [83]

The metal that is used in media is Nickel while the insulator used in media is silicon.

<h3>What is a metal?</h3>

Metals are those elements that occur at the left hand side of the periodic table. A metal that is very useful in media is nickel because it is very pure and can be used in electronics circuits.

However, an insulator that is used in media is silicon which is used integrated circuits.

Learn more about metals: brainly.com/question/16759172

8 0
2 years ago
4- 4110 kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in th
Nat2105 [25]

The correct question is: 10 kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.

Answer: The temperature is 21.6^{o}C and total enthalpy when the heating is completed is 300 kJ.

Explanation:

Given: Mass = 10 kg

Volume = 14 L

Final pressure = 600 K

First, convert volume from L to m^{3}/kg as follows.

v_{1} = \frac{14 \times 10^{-3}}{10}\\= 0.0014 m^{3}/kg

According to the R-134a tables at 300 kPa and 0.0014 m^{3}/kg.

h_{1} = 54.6 kJ/kg

T_{sat} = 0.7 C

u_{1} = 54.1 kJ/kg

Now, at the state 2 p_{2} = 600 kPa and v_{2} = v_{1} = 0.0014 m^{3}/kg

This means that the final temperature at state 2 is T_{2} = T_{sat} = 21.6^{o}C

Hence, the change in enthalpy is calculated as follows.

\Delta H = m(h_{2} - h_{1})\\= 10(84.6 - 54.6)\\= 300 kJ

The first law is applied to transfer the heat transfer as follows.

Q = m(u_{2} - u_{1})\\= 10(83.8 - 54.1) kJ\\= 297 kJ

Thus, we can conclude that the temperature is 21.6^{o}C and total enthalpy when the heating is completed is 300 kJ.

3 0
3 years ago
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