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Brums [2.3K]
3 years ago
9

Find the value of x in the figure below. Assume that the lines are parallel

Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0
C

work:

75 is equal to 2x+15

75-15 = 60

60/2 = 30

x=30
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2 balloons and 3 cakes cost $26.
mel-nik [20]

Answer:

The cost of one balloon is 4 dollars

the cost of one cake is 6 dollars

Step-by-step explanation:

The way I did it was by substituting different numbers and seeing if they equaled forty or 26.

my thought process:

1 balloon= 5

1 cake= 10

that doesnt work for 2 balloons and 3 cakes

1 balloon=5

1 cake=5

that works for 4 balloons and 4 cakes but not 2 balloons and 3 cakes

1 balloon=4

1 cake=7

I'm sorry I'm way too tired to finish this 0-0 anyways yeah that's the correct answer :)

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3 years ago
The bottom of a rectangular swimming pool has an area of 512 feet2. If the length of the
dexar [7]
The width is 32
Divide 512 by 16
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2 years ago
Ms. Figgs asked 25 students in her 7th grade homeroom to select their favorite cookie. The results are recorded in the table bel
iren [92.7K]

Answer:

120

Step-by-step explanation:

3 0
3 years ago
Help I need help on 4 help me as soon as possible and show me the equation
levacccp [35]
I think the equation would be

10,000 - ( 150/sec)
4 0
3 years ago
4- A manufacturing process produces items whose weights are normally distributed. It is known that 22.57% of all the items produ
galben [10]

Answer:

\\ \mu = 118\;grams\;and\;\sigma=30\;grams

Step-by-step explanation:

We need to use z-scores and a standard normal table to find the values that corresponds to the probabilities given, and then to solve a system of equations to find \\ \mu\;and\;\sigma.

<h3>First Case: items from 100 grams to the mean</h3>

For finding probabilities that corresponds to z-scores, we are going to use here a <u>Standard Normal Table </u><u><em>for cumulative probabilities from the mean </em></u><em>(Standard normal table. Cumulative from the mean (0 to Z), 2020, in Wikipedia) </em>that is, the "probability that a statistic is between 0 (the mean) and Z".

A value of a z-score for the probability P(100<x<mean) = 22.57% = 0.2257 corresponds to a value of z-score = 0.6, that is, the value is 0.6 standard deviations from the mean. Since this value is <em>below the mean</em> ("the items produced weigh between 100 grams up to the mean"), then the z-score is negative.

Then

\\ z = -0.6\;and\;z = \frac{x-\mu}{\sigma}

\\ -0.6 = \frac{100-\mu}{\sigma} (1)

<h3>Second Case: items from the mean up to 190 grams</h3>

We can apply the same procedure as before. A value of a z-score for the probability P(mean<x<190) = 49.18% = 0.4918 corresponds to a value of z-score = 2.4, which is positive since it is after the mean.

Then

\\ z =2.4\;and\; z = \frac{x-\mu}{\sigma}

\\ 2.4 = \frac{190-\mu}{\sigma} (2)

<h3>Solving a system of equations for values of the mean and standard deviation</h3>

Having equations (1) and (2), we can form a system of two equations and two unknowns values:

\\ -0.6 = \frac{100-\mu}{\sigma} (1)

\\ 2.4 = \frac{190-\mu}{\sigma} (2)

Rearranging these two equations:

\\ -0.6*\sigma = 100-\mu (1)

\\ 2.4*\sigma = 190-\mu (2)

To solve this system of equations, we can multiply (1) by -1, and them sum the two resulting equation:

\\ 0.6*\sigma = -100+\mu (1)

\\ 2.4*\sigma = 190-\mu (2)

Summing both equations, we obtain the following equation:

\\ 3.0*\sigma = 90

Then

\\ \sigma = \frac{90}{3.0} = 30

To find the value of the mean, we need to substitute the value obtained for the standard deviation in equation (2):

\\ 2.4*30 = 190-\mu (2)

\\ 2.4*30 - 190 = -\mu

\\ -2.4*30 + 190 = \mu

\\ \mu = 118

7 0
3 years ago
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