Proof Pythagorean identities:

Pleaase. please please help i will mark brainliest

Mademuasel [1]

Answer:

b

Step-by-step explanation:

8 0

2 years ago

A regression was run to determine if there is a relationship between hours of TV watched per day (x) and number of situps a pers

Arturiano [62]

Answer:

A person who watches 8.5 hours of TV can do 30.4 sit ups.

Step-by-step explanation:

The regression equation is used to predict or estimate the value of the response (or dependent) variables using the information about the explanatory (or predictor) variables.

The general form of a regression equation is:

$y=ax+b$

Here,

y = dependent variable

x = independent variable

a = intercept

b = slope

The regression equation representing the relationship between hours of TV watched per day (x) and number of sit ups a person can do (y) is:

$y=-0.74x+36.359$

Compute the number of sit ups a person who watches 8.5 hours of TV can do as follows:

$y=-0.74x+36.359$

$=(-0.74\times 8.5)+36.359\\=-6.29+36.659\\=30.369\\\approx 30.4$

Thus, a person who watches 8.5 hours of TV can do 30.4 sit ups.

6 0

3 years ago

Alicia has a gold bracelet and a silver bracelet. She has a black ring, a blue ring, a brown ring, and a white ring. She also ha

Artist 52 [7]

This may not be the right answer but I do believe it is 16 different combinations

8 0

3 years ago

a navy submarine descended from sea leval at a rate of 7 feet per second. write the descent rate and the sub's elevation after 1

valina [46]

The descent rate is 7 feet/second. the subs elevation would be 7 x 10(60) which is 7x 600the sub's elevation would therefore be 4,200 feet below sea level

4 0

2 years ago

A Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer; a sample

8090 [49]

Answer:

Step-by-step explanation:

Step(i):-

Given first random sample size n₁ = 500

Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.

First sample proportion

$p^{-} _{1} = \frac{65}{500} = 0.13$

Given second sample size n₂ = 700

Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.

second sample proportion

$p^{-} _{2} = \frac{133}{700} = 0.19$

Level of significance = α = 0.05

critical value = 1.96

Step(ii):-

Null hypothesis : H₀: There is no significance difference between these proportions

Alternative Hypothesis :H₁: There is significance difference between these proportions

Test statistic

$Z = \frac{p_{1} ^{-}-p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }$

where

$P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2} }{n_{1}+ n_{2} } = \frac{500 X 0.13+700 X0.19 }{500 + 700 } = 0.165$

Q = 1 - P = 1 - 0.165 = 0.835

$Z = \frac{0.13-0.19 }{\sqrt{0.165 X0.835(\frac{1}{500 } +\frac{1}{700 } )} }$

Z = -2.76

|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance

Null hypothesis is rejected at 0.05 level of significance

Alternative hypothesis is accepted at 0.05 level of significance

Conclusion:-

There is there is a difference between these proportions at α = 0.05

3 0

2 years ago