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Oksanka [162]
3 years ago
6

Proof Pythagorean identities:

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0
<h2>Sorry, But I don't know!!</h2>
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Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of
Nata [24]
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
7 0
3 years ago
Identify as many solutions to the equation below as you can.<br> x + y = 12
harkovskaia [24]

Answer:

infinite

Step-by-step explanation:

because there is an infinite amount of numbers there is an infinite amount of solutions

5 0
2 years ago
What two numbers is 94 between
levacccp [35]
94 is between 93 and 95
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3 years ago
Read 2 more answers
Barry has $2 less than Alex.
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Alex has $14, Barry has $12 and Carl has $9

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Which reason justifies the last step in a proof that ΔEDG≌ΔADC?
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It is side angle side postulate 
fd is congruet to db
ed is congruent to da
and vertical angles theorem
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