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zysi [14]
3 years ago
10

Please help me it’s due in 10 minutes

Chemistry
1 answer:
shtirl [24]3 years ago
5 0

Answer:

please the answer is changes in climate

(sorry if I'm wrong )

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Can some help me ....
goldfiish [28.3K]

Answer:

cool and dim ........nn

3 0
3 years ago
How can a chemical reaction be sped up?Select from the drop-down menu to correctly complete the statement.
lara31 [8.8K]

Answer: Catalyst

Explanation: it speeds it up lol but basically the catalyst helps speed up the chemical reaction by reducing the activation energy or changing the reaction machenism/

8 0
3 years ago
Consider the following reactants:
sdas [7]

Answer:

A. 3NaOH(aq)+Fe(NO3)3(aq) ---> Fe(OH)3 (solid)+ 3NaNO3(aq)

B. Double replacement reaction

AB +CD ---> AD + CB

4 0
3 years ago
Which of the following molecules is amphipathic?
raketka [301]

Answer:

B) CH3(CH2)10CO2H

Explanation:

Hello,

In this case, we define amphipathic as a compound having both a hydrophilic and a hydrophobic part, for that reason, the hydrophilic part will be water-soluble (polar) whereas the hydrophobic does not (nonpolar). In such a way, some functional groups such as hydroxyl and carboxyl tend to be polar by cause of the presence of O-H bonds whereas long-carboned chains tend to be nonpolar by cause of the presence of C-H and C-C bonds.

Therefore, since A) CH3CH2OH (ethanol) and D) CH3CO2H (acetic acid) are short-carboned chains with polar groups they are largely hydrophilic whereas C) CH3(CH2)10CH3 (dodecane) is highly nonpolar, we sum up that only B) CH3(CH2)10CO2H (dodecanoic acid or lauric acid) is amphoteric as it has a long-charboned part (nonpolar) and a water-soluble part (polar).

Best regards.

7 0
4 years ago
Consider the following reaction: NH4I(s) NH3(g) + HI(g) If a flask maintained at 674 K contains 0.138 moles of NH4I(s) in equili
xz_007 [3.2K]

Answer:

4.08 × 10⁻³

Explanation:

Step 1: Write the balanced reaction at equilibrium

NH₄I(s) ⇄ NH₃(g) + HI(g)

Step 2: Calculate the equilibrium constant

The equilibrium constant (K) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. Only gases and aqueous species are included.

K = [NH_3] \times [HI] = 4.34 \times 10^{-2}  \times 9.39 \times 10^{-2} = 4.08 \times 10^{-3}

4 0
4 years ago
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