Question

1. Consider the reaction of magnesium metal with hydrochloric acidity produce magnesium chloride and hydrogen gas. If 36.03g of magnesium and 55.10g of hydrochloric are reacted , how many grams of hydrogen gas are produced?
2. How many magnesium chloride are formed from the previous reaction?

Answer 1

Answer:

Mass magnesium chloride produced =  71.88g

Mass of hydrogen gas produced =  1.51 g

Explanation:

Given data:

Mass of magnesium = 36.03 g

Mass of HCl = 55.10 g

Mass of hydrogen gas produced = ?

Mass of magnesium chloride produced = ?

Solution:

Chemical equation:

Mg + 2HCl     →    MgCl₂ + H₂

Number of moles of Mg:

Number of moles = mass/molar mass

Number of moles = 36.03 g/ 24.3 g/mol

Number of moles = 1.48 mol

Number of moles of HCl:

Number of moles = mass/molar mass

Number of moles = 55.10 g/ 36.5 g/mol

Number of moles = 1.51 mol

Now we will compare the moles of hydrogen and magnesium chloride with HCl and Mg.

                            Mg            :           H₂

                             1               :            1

                            1.48          :          1.48

                          HCl            :            H₂  

                            2              :             1

                           1.51            :          1/2×1.51 = 0.755

Mass of hydrogen:

Mass = number of moles × molar mass

Mass = 0.755mol × 2 g/mol

Mass = 1.51 g

                            Mg            :           MgCl₂

                             1               :            1

                            1.48          :          1.48

                          HCl            :            MgCl₂

                            2              :             1

                           1.51            :          1/2×1.51 = 0.755

Mass of magnesium chloride:

Mass = number of moles × molar mass

Mass = 0.755mol × 95.211g/mol

Mass =  71.88g