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Kazeer [188]
3 years ago
15

You are riding in a hot air balloon on Valentine’s Day withyour sweetheart. As you get ready to set your balloon downyou notice

that while your balloon is 500 ft above ground, your friends balloon is 800 ft above ground. The plan is for both balloons to descend straight down. Your balloon willland right at the edge of the lake below, but it appears thatyour friends will be pretty far away. You can see a reflectionof their balloon right in the middle (direct center) of the 1200 ft wide lake below.How far away from the lake will your friends touch down?
(Don't mind my scribbles maybe they will help, maybe not)

Mathematics
1 answer:
densk [106]3 years ago
7 0

Answer:

Try 750 ft?

Step-by-step explanation:

Proportion:

800/500 = 1,200/x

Solve:

1,200 / 800 = 1.5

1.5 * 500 = 750

Hope this helped!

Please mark as brainliest!

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PLEASE HELP ME!! WILL MARK BRAINLIST!!
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3 years ago
-3(2y+4) is greater that equal to 12-4y<br>​
ipn [44]

Answer:

y is less than or equal to -12

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Step-by-step explanation:

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Jason and Martin want to share 3 cookies equally. How much cookie will Jason and Martin each receive? Write an equation and expr
Verdich [7]

Answer: each will get 3/2

Step-by-step explanation:

They will each get a whole cookie with one left over that they can break in half.

6 0
3 years ago
What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0
3 years ago
I need help with this whole page
attashe74 [19]
Number 1 is correct
Number 2: you just have to divide like in number one
Number 3: add 9.72 plus 5.40 and divide by 2
5 0
3 years ago
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