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grigory [225]
2 years ago
10

Coach Withrite can bench press 325 lbs. How many kg can he bench?

Mathematics
1 answer:
puteri [66]2 years ago
6 0

Answer:

147.18 Kgs

Step-by-step explanation:

1 Kg= 2.2 lbs

325/2.2=kg

147.18 Kgs

<em>Hope his helped! Have a good day!</em>

<em>All rewards appreciated!</em>

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n=42

Step-by-step explanation:

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3 years ago
Imagine you have a job working at a pizza shop, and you make $400 in one week, but $100 Is withheld from your
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You would make 1200 because of taxes. That all I know sorry
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I need help please.
sweet-ann [11.9K]

Answer:

<u>Third Option</u>: y = \frac{5}{4}x

Step-by-step explanation:

Given the points on the graph, (4, 5) and (-4, -5):

In order to determine the equation of the given graph in slope-intercept form, y = mx + b:

Use the given points to solve for the slope:

Let (x₁, y₁) = (-4, -5)

(x₂, y₂) = (4, 5)

m = (y₂ - y₁)/(x₂ - x₁)

m = \frac{5 - (5)}{4 - (-4)}  = \frac{5 + 5}{4 + 4}  = \frac{10}{8} = \frac{5}{4}

Therefore, the slope of the line is: m = \frac{5}{4}.

Next, use one of the given points on the graph, (4, 5) to solve for the y-intercept, b:

y = mx + b

5 = \frac{5}{4} (4) + b

5 = 5 + b

5 - 5 = 5 - 5 + b

0 = b

Therefore, the linear equation in slope-intercept form is: y = \frac{5}{4}x.  The correct answer is Option 3.

8 0
2 years ago
The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?
Serhud [2]

Answer:

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

Step-by-step explanation:

Given - The circumference of the ellipse approximated by C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi }  =  \sqrt{\frac{a^{2} + b^{2} }{2} }

Squaring Both sides, we get

[\frac{C}{2\pi }]^{2}   =  [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2}  }   =  {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2}  }   =  {{a^{2} + b^{2} }

\frac{C^{2} }{2(\pi )^{2} }  = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} }  -  a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}  = b

∴ we get

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

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