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3 years ago

Find the volume of the rectangular prism.

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

8 0

Answer:

I think 8

Step-by-step explanation:

Btw love your pfp tell meh if it’s wrong I’ll try and fix it

Andreas93 [3]3 years ago

6 0

Answer:

5/18 m

Step-by-step explanation:

You are going to multiply length x width x Height

5/6 x 1/2 x 2/3

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66/9-7*532<br><br> Am I cute and I do feel really insecure about myself toooo....

miv72 [106K]

Answer:

− 11150 /3

Step-by-step explanation:

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3 0

3 years ago

You buy (m+5) bagels at 35 cents each. How much is the cost?

Montano1993 [528]

Answer:

35M+175

Step-by-step explanation:

35(M+5)=35M+175

6 0

4 years ago

The number of gnats G(x), in millions, in a certain area depends on the May rainfall x, in inches. That relationship can be expr

puteri [66]

Answer:

9 inches of rainfall produces the maximum number of gnats.

Step-by-step explanation:

Given : $G(x) = - x^2 + 18x$

To Find :How many inches of rainfall produces the maximum number of gnats?

Solution:

$G(x) = - x^2 + 18x$

G(x) =The number of gnats in millions.

x denotes the length of rainfall

To Find the maximum length find the mid point of zeroes .Since parabolas are symmetrical, the x value of the max falls 1/2 way between the zeros.

$0= - x^2 + 18x$

$0= x^2-18x$

$0= x(x-18)$

So, x = 0 , x= 18

Now Formula of midpoint : $x=\frac{x_1+x_2}{2}$

$x=\frac{0+18}{2}$

$x=9$

Hence 9 inches of rainfall produces the maximum number of gnats.

8 0

3 years ago

In a certain state, license plates each consist of 2 letters followed by either 3 or 4 digits. How many differen license plates

coldgirl [10]

Answer:

26 × 26 × 10 × 10 × 10 = 676 , 000 possibilities

Step-by-step explanation:

There is nothing stating that the letters and numbers can't be repeated, so all 26 letters of the alphabet and all 10

digits can be used again.

If the first is A, we have 26 possibilities:

AA, AB, AC,AD,AE ...................................... AW, AX, AY, AZ.

If the first is B, we have 26 possibilities:

BA, BB, BC, BD, BE .........................................BW, BX,BY,BZ

And so on for every letter of the alphabet. There are 26 choices for the first letter and 26 choices for the second letter. The number of different combinations of 2 letters is: 26 × 26 = 676

The same applies for the three digits. There are 10 choices for the first, 10

for the second and 10 for the third:

10 × 10 × 10 = 1000

So for a license plate which has 2 letters and 3 digits, there are: 26 × 26 × 10 × 10 × 10 = 676 , 000 possibilities.

Hope this helps.

8 0

3 years ago

Use the Fundamental Counting Principle to solve.

Vedmedyk [2.9K]

$number \: of \: performances = 9 \\ note = \\ one \: insists \: on \: being \: last \\ number \: of \: flexible \: performances = 9 - 1 = 8 \\ \\ c( \gamma ) = 8P8 \times 1 \\ c( \gamma ) = 8! \\ c( \gamma ) = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \\ c( \gamma ) = 40320 \: ways$

7 0

2 years ago