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Mice21 [21]
2 years ago
5

If 15% of 4x is 20 less than x, what is the value of x?

Mathematics
1 answer:
Bess [88]2 years ago
4 0

The sentence "15% of 4x is 20 less than x"

translates to    0.15 • (4x)  = x – 20

Solving that…

    0.15(4x) = x - 20           multiplipy 0.15•4

          0.6x = x - 20           subtract x from both sides

         -0.4x = - 20              divide both sides by -0.4

                x = 50

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The area of a rectangle is 259 cm2 and its lenght is 18.5 cm find
crimeas [40]

The breadth of rectangle is 14 cm

The perimeter of rectangle is 65 cm

<em><u>Solution:</u></em>

Given that,

Area of rectangle = 259 square centimeter

Length of rectangle = 18.5 cm

<em><u>The area of rectangle is given by formula:</u></em>

Area\ of\ rectangle = length \times breadth

<h3><u>Find the breadth:</u></h3>

Substitute the given values in above formula:

259 = 18.5 \times breadth\\\\breadth = \frac{259}{18.5}\\\\breadth = 14

Thus breadth is 14 cm

<h3><u>Find the perimeter:</u></h3>

The perimeter of rectangle is given by formula:

Perimeter = 2(length + breadth)

Substitute the given values in above formula:

perimeter = 2(18.5+14)\\\\perimeter = 2(32.5)\\\\perimeter = 65

Thus perimeter of rectangle is 65 cm

7 0
2 years ago
About 150,000 people live in a circular region with a population density of about
morpeh [17]

Area of a circle = pi x r^2

Area of circle = 150,000/ 1578 = 95.06 square miles

95.06 = 3.14 x r ^2

Divide both sides by 3.14

R^2 = 30.27

Find the square root:

R = sqrt(30.27)

R = 5.5

The radius is c) 5.5 miles

8 0
3 years ago
10.55 = as a simplest form​
Katarina [22]

Answer:

10 11/20

as a fraction.

Step-by-step explanation:

.55 is 55/100 but can be simplified. 55 and 100 can be divided by 5 so it goes to 11 and 20

5 0
3 years ago
HELP!! NUMBER PATTERNS, Rule: Add 15, subtract 10. First term: 4
Verizon [17]
It is 9 for 4+15-10.
5 0
3 years ago
Read 2 more answers
A little help Mean median mode range
goldenfox [79]

Answer:

Mean, median, and mode are three kinds of "averages". There are many "averages" in statistics, but these are, I think, the three most common, and are certainly the three you are most likely to encounter in your pre-statistics courses, if the topic comes up at all.

The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers. The "median" is the "middle" value in the list of numbers. To find the median, your numbers have to be listed in numerical order from smallest to largest, so you may have to rewrite your list before you can find the median. The "mode" is the value that occurs most often. If no number in the list is repeated, then there is no mode for the list.

Mean, Median, Mode, and Range

The "range" of a list a numbers is just the difference between the largest and smallest values.

   Find the mean, median, mode, and range for the following list of values:

13, 18, 13, 14, 13, 16, 14, 21, 13

The mean is the usual average, so I'll add and then divide:

(13 + 18 + 13 + 14 + 13 + 16 + 14 + 21 + 13) ÷ 9 = 15

Note that the mean, in this case, isn't a value from the original list. This is a common result. You should not assume that your mean will be one of your original numbers.

The median is the middle value, so first I'll have to rewrite the list in numerical order:

13, 13, 13, 13, 14, 14, 16, 18, 21

There are nine numbers in the list, so the middle one will be the (9 + 1) ÷ 2 = 10 ÷ 2 = 5th number:

13, 13, 13, 13, 14, 14, 16, 18, 21

So the median is 14.

The mode is the number that is repeated more often than any other, so 13 is the mode.

The largest value in the list is 21, and the smallest is 13, so the range is 21 – 13 = 8.

mean: 15

median: 14

mode: 13

range: 8

Note: The formula for the place to find the median is "([the number of data points] + 1) ÷ 2", but you don't have to use this formula. You can just count in from both ends of the list until you meet in the middle, if you prefer, especially if your list is short. Either way will work.

Step-by-step explanation:

4 0
3 years ago
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