Ask question

Ask question

All categories

3 years ago

9

Solve this system by substitution. y = 5x - 15 y = 2x - 6 *Remember to write your answer as a coordinate point (x,y Solve this s

ystem by substitution

1 answer:

oksano4ka [1.4K]3 years ago

7 0

5x - 15 = 2x - 6
3x = 9
x = 3
Y = 5(3) - 15
Y = 0
(3,0)

You might be interested in

Austin earns $9.75 an hour at a part-time job, and earns $12 each time mowing lawns in the neighborhood. They graph the amount o

kaheart [24]

Answer:

$7.25 at part-time job

$9.00 every time lawn mowed

so he would get 33.33 day so we will just say 33 times to get 300 dollars if he gets $9 for mowing. And 41.37 hours to get $300 and he would have to use x and y graph to find the boundary line.

Step-by-step explanation:

4 0

2 years ago

I will give brainliest answer pls help

zaharov [31]

Answer:

C

Step-by-step explanation:

1/4= 0.25

8 0

3 years ago

Read 2 more answers

Use the following stem-and-leaf plot to answer the question.<br><br><br>What is the median?

pishuonlain [190]

The median of the stem-and-leaf plot is 23

7 0

3 years ago

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=

Leno4ka [110]

1 step: $S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}$ , $S_{3}=T_{1}+T_{2}+T_{3}$ , then
$S_{5}-S_{3}=T_{4}+T_{5}=5$ .

2 step: $T_{n}=T_{1}*q^{n-1}$ , then
$T_{6}=T_{1}*q^{5}$
$T_{5}=T_{1}*q^{4}$
$T_{4}=T_{1}*q^{3}$
$T_{3}=T_{1}*q^{2}$
and $\left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right.$ will have form $\left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right.$ and dividing first equation on second we obtain $\frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}$ . So, $\frac{(q-1)(q+1)}{q+1} = \frac{1}{2}$ and $q-1= \frac{1}{2}$ , $q= \frac{3}{2}$ - the common ratio.

4 step: Insert $q= \frac{3}{2}$ into equation $T_{1}*q^{3}*(q+1)=5$ and obtain $T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5$ , from where $T_{1}= \frac{16}{27}$ .

5 0

3 years ago

Find the area of the polygon with the given vertices x(2,4) y(0,-2) z(2,-2)

weeeeeb [17]

Answer:

6

Step-by-step explanation:

b = 2 units

h = 6 units

A=1/2 *b*h

= 1/2 *6*2

= 6

8 0

2 years ago