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evablogger [386]

3 years ago

9

Jill has 15 oranges and 12 pears. She wants to put all of the fruit into baskets with each basket having the SAME NUMBER of piec

es of fruit in it. Without mixing the fruit, what is the GREATEST number of pieces of fruit Jill can put in each basket?

1 answer:

aleksandr82 [10.1K]3 years ago

8 0

Y’all need help ASAP thanks for

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PLEASE HELP QUICK

valentinak56 [21]

Answer: 28 in.

Step-by-step explanation:

its simple

7 0

3 years ago

Perpendicular Lines please help me guys I'm lostt

mamaluj [8]

9 = 2(6) - b
9 = 12 - b
-3 = b

4 0

3 years ago

Which value of HNK are used to write the function f(x) = x2 + 12x + 6 in vertex form?

anygoal [31]

Answer:

( − 6 , − 30 )

Step-by-step explanation:

Rewrite in vertex form and use this form to find the vertex ( h , k ) .

6 0

2 years ago

What's the solution to -182=2(1+2x)-2

MatroZZZ [7]

-182=2(1+2x)-2

2*1=2
2*2x=4x

-182=4x+2-2
-182=4x
-45.5=x

8 0

2 years ago

Read 2 more answers

Find the area of following rhombuses. Round your answers to the nearest tenth if<br> necessary.

polet [3.4K]

Answer:

$Area =55.4ft^2$

Step-by-step explanation:

Given

The attached rhombus

Required

The area

First, calculate the length of half the vertical diagonal (x).

Length x is represented as the adjacent to 60 degrees

So, we have:

$\tan(60) = \frac{4\sqrt 3}{x}$

Solve for x

$x = \frac{4\sqrt 3}{\tan(60)}$

$\tan(60) = \sqrt 3$

So:

$x = \frac{4\sqrt 3}{\sqrt 3}$

$x = 4$

At this point, we have established that the rhombus is made up 4 triangles of the following dimensions

$Base = 4\sqrt 3$

$Height = 4$

So, the area of the rhombus is 4 times the area of 1 triangle

$Area = 4 * \frac{1}{2} * Base * Height$

$Area = 4 * \frac{1}{2} * 4\sqrt 3 * 4$

$Area =2 * 4\sqrt 3 * 4$

$Area =55.4ft^2$

7 0

3 years ago