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JulijaS [17]
3 years ago
7

The graph of f(x) is given on the right.

Mathematics
2 answers:
aleksklad [387]3 years ago
7 0

Answer:

-1,3

Step-by-step explanation:

zloy xaker [14]3 years ago
6 0
The awnser is -1,3 I think
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What is the solution to the equation? 2x - 4 = 6
rusak2 [61]

Answer:

x = 5

Step-by-step explanation:

2x -4 = 6

Add +4 on both sides

2x = 10

Divide by 2

x = 5

6 0
3 years ago
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You weigh six packages and find the weights to be 34, 24, 74, 29, 69, and 64 ounces. If you include a package that weighs 154 ou
saw5 [17]

Answer:

C. the mean increases more

Step-by-step explanation:

the mean is more affected by outliers because it is an average of all the numbers.

7 0
3 years ago
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Person who answers first I will give 30 points needed asap​<br>what is AoC<br>BoC <br>DoE<br>​
Degger [83]

Answer:

First of AOD is verticallly opposite to BoC which makes it 55°

Angle at AoC is 55°+55°+105° minus 360 which is 145° hope this helps

7 0
3 years ago
Find the equation of a circle with a center at (–7, –1) where a point on the circle is (–4, 3).
gogolik [260]

Answer:

(x + 7)^2 + (y + 1)^2 = 25.

Step-by-step explanation:

The center of a circle is easy to set up. According to the formula below, the formula for the circle will be (x - a)^2 + (y - b)^2 = r^2.

In this case, a = -7 and b = -1, so we have...

(x - (-7))^2 + (y - (-1))^2 = r^2

(x + 7)^2 + (y + 1)^2 = r^2

To get the radius, we need to find the distance between the center and the point on the circle. The distance formula is d = sqrt((x2 - x1)^2 + (y2 - y1)^2).

In this case, x2 = -4, x1 = -7, y2 = 3, and y1 = -1.

sqrt((-4 - -7)^2 + (3 - -1)^2) = sqrt((-4 + 7)^2 + (3 + 1)^2) = sqrt((3)^2 + (4)^2) = sqrt(9 + 16) = sqrt(25) = plus or minus 5.

Since distance can only be positive, the distance is 5 units, meaning that the radius is 5 units.

5^2 = 25

So, your equation should be (x + 7)^2 + (y + 1)^2 = 25.

Hope this helps!

8 0
3 years ago
How many whole numbers are there, whose squares and cubes have the same number of digits?
Naddik [55]

Answer:

there are only 4 whole numbers whose squares and cubes have the same number of digits.

Explanations:

let 0, 1, 2 and 4∈W (where W is a whole number), then

0^2=0, 0^3=0,

1^2=1, 1^3=1,

2^2=4, 2^3=8,

4^2=16, 4^3=64.

You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits







7 0
3 years ago
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