Ask question

Ask question

All categories

3 years ago

11

10n + 0.3 = 0.1n + 0.3

1 answer:

egoroff_w [7]3 years ago

6 0

Answer:

n = 0

Step-by-step explanation:

Let's solve for n, according to the linear equation given, this way:

10n + 0.3 = 0.1n + 0.3

10n - 0.1n = 0.3 - 0.3 (Like terms)

9.9n = 0

n = 0/9.9

<u>n = 0</u>

You might be interested in

Can anyone help??

skad [1K]

make two triangles. make the bottom of one triangle 135 as the shadow and "x" as the height. the other traingle should have 9 at the bottom and 5.3 as the height. then make a proportion

3 0

3 years ago

1. Twelve large bottles of water cost $9.

Vaselesa [24]

Answer:1. $3- 4 bottles, 1 bottle = 4/3 , 7 bottles= 28/3

2. 40 pounds=$32, 1 pound= $8/10

3. Per bag= 3/2, 7bags= 21/2

4. Per book = $3, 21 books= $63

5. Per bracelet = 0.25 cents, 11 bracelets = 2 dollars 75 cents

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago

If the point (−1,3) is translated according to the rule (x,y)→(x+4,y−2), and then reflected across the x-axis, what are the coor

Artemon [7]

Answer:

hi

Step-by-step explanation:

rfshs hmm jtutq JK jehewyywgu

5 0

2 years ago

Read 2 more answers

At which points are the equations y=x^2+3x+2 and y=2x+3 approximately equal

ASHA 777 [7]

so x^2 + 3x + 2 = 2x+3

or x^2 + x = 1

After that just use the a quadratic equation formula

6 0

3 years ago