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liberstina [14]
3 years ago
10

PS.

Chemistry
1 answer:
Scrat [10]3 years ago
6 0
The anwser is A thank you
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Calculate the volume of a 1.25 M solution of HCN made from 31 grams of HCN
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Answer:

V HCNsln = 0.9176 L

Explanation:

V HCNsln = ?

∴ m HCN = 31 g

∴ <em>C</em> HCNsln = 1.25 mol/L

∴ molar mass HCN = 27.0253 g/mol

⇒ V HCNsln = (31 g)*(mol/27.0253 g)*(L/1.25 mol) = 0.9176 Lsln

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y

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electron: orbiting around the nucleus

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Two moles of phosphoric acid (H3PO4) contain, respectively: "x" moles of hydrogen atoms, "y" moles of phosphorous atoms, "z" mol
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d)

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