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Inga [223]
3 years ago
7

1. What is the solution of n^2-49=0?

Mathematics
1 answer:
Effectus [21]3 years ago
7 0

<u>Answer:</u>

<h2>1. a</h2><h2>2. b</h2><h2>3. b</h2><h2>4. b</h2><h2>5. 22</h2>

<u>Explanation:</u>

1.

n²-49=0

n=√49

n=7

2.

x²+64=0

x=√64

x=8

3.

if A=144x²

l = √A

l = √(144x²)

l = 12x

4.

b = (24×2)/3b

b = 48/3b

b = 16/b

b² = 16

b = √16

b = 4 in <em>(-4 is correct in algebra but there's no negative lengths in geometric shapes)</em>

5.

x²+z = 103

x² = 103-z

x = √(103-z)

for x = -9 and 9    (103-z) must equal 81

z = 103 - 81 = 22

x = √(103-22)

x = √81

x = -9 , 9

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3 years ago
Can someone help me please
gizmo_the_mogwai [7]
The answer is 25 chicks

Reasoning:

This is a simple problem.
Consider you are the only chick that matters, and construct a table to say whether YOU get pecked. Your chance of being pecked comes down to only 4 outcomes. (1) YES - pecked twice. (2) YES - pecked from left wing only. (3) YES - pecked from right wing only. (4) NO - unpecked.
The table has 4 elements, all of equal probability, 1 of which is unpecked. YOU are therefore pecked 3:1 ratio or 3:4 opportunities  75% of the time. For convenience, this needs to be conducted for 100 trials of YOU, and the answer is that 25 times YOU will NOT be pecked. The circular nature of the 100 chicks says that YOU are not unique, and your experience is the same as the others, so we extrapolate your experience of 100 trials to a single trial of 100 chicks just like YOU. 25 unpecked chicks, 50 get pecked once, 25 get double pecks.

This is the same table constructed for 100 women having two children and asking how many have no girls.
7 0
3 years ago
Write an inequality that represents this situation below. Be sure to define your variable in words.
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Rudiy27

Answer:

Step-by-step explanation:

you have a special triangle 30-60-90

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