What is the solution set of 4x^2-36= 0? (-3) (3) (-3,3)

Mathematics

2 answers:

PtichkaEL [24]3 years ago

8 0

Answer:

(-3, 3)

Step-by-step explanation:

The equation is:

$4x^2-36=0$

to clear for x, first we move the -36 to the right as a +36 (or you can also say that we add 36 to both sides):

$4x^2=36$

dividing by 4:

$x^2=36/4\\x^2=9$

taking the square root:

$x=$ ± $\sqrt{9}$

we add the ± because a square root has two solutions, a positive one, and a negative one.

Then we get:

$x=$ ± 3

The solutions are -3 and +3

which is represented in the option (-3, 3)

ololo11 [35]3 years ago

6 0

Answer:

(-3, 3).

Step-by-step explanation:

4x^2-36= 0

4x^2 = 36 Taking square roots of both sides:

2x = +/- 6

x = +/- 3.

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