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NikAS [45]
3 years ago
8

What is the solution set of 4x^2-36= 0? (-3) (3) (-3,3)

Mathematics
2 answers:
PtichkaEL [24]3 years ago
8 0

Answer:

(-3, 3)

Step-by-step explanation:

The equation is:

4x^2-36=0

to clear for x, first we move the -36 to the right as a +36 (or you can also say that we add 36 to both sides):

4x^2=36

dividing by 4:

x^2=36/4\\x^2=9

taking the square root:

x= ± \sqrt{9}

we add the ±  because a square root has two solutions, a positive one, and a negative one.

Then we get:

x= ± 3

The solutions are -3 and +3

which is represented in the option (-3, 3)

ololo11 [35]3 years ago
6 0

Answer:

(-3, 3).

Step-by-step explanation:

4x^2-36= 0

4x^2 = 36    Taking square roots of both sides:

2x = +/- 6

x = +/- 3.

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If BTS=GHD BS=25 TS=14 BT=31 GD=4x-11 S=56 B=21 and H=(7y+5) find the values of x and y
77julia77 [94]

Given:

Consider the completer question is "If ∆BTS≅∆GHD, BS=25, TS=14, BT=31, GD=4x-11, m∠S=56, m∠B=21 and m∠H=(7y+5), find the values of x and y.

To find:

The values of x and y.

Solution:

We have,

\Delta BTS\cong \Delta GHD       (Given)

BS=GD                       (CPCTC)

25=4x-11

25+11=4x

36=4x

Divide both sides by 4.

9=x

In ∆BTS,

\angle B+\angle T+\angle S=180^\circ    (Angle sum property)

21^\circ+\angle T+56^\circ=180^\circ

77^\circ+\angle T=180^\circ

\angle T=180^\circ-77^\circ

\angle T=103^\circ

Now,

\angle T=\angle H            (CPCTC)

103=7y+5

103-5=7y

98=7y

Divide both sides by 7.

14=y

Therefore, the value of x is 9 and value of y is 14.

3 0
3 years ago
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Nastasia [14]
Hey, ok so 1) is A  
2) is C
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How i go this is you just take each number and plug it in like 10 all you had to do was take one of the numbers in the answers and put it in as m like this 426/3=142 and see if that works. I would use a calculator <span />
5 0
3 years ago
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