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Verizon [17]
3 years ago
9

Write an equation of the line with slope -2 and passing through (3,1) in slope-intercept form

Mathematics
1 answer:
Vinvika [58]3 years ago
8 0

Answer:

y=-2x+7

Step-by-step explanation:

Hi there!

The form of slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept

We are given the slope (-2) and a point (3,1)

We can immediately substitute -2 as the slope in the equation

y=-2x+b

Now we need to find b

Because the line will pass through the point (3,1), we can use it to solve for b

Substitute 3 as x and 1 as y

1=-2(3)+b

multiply

1=-6+b

add 6 to both sides to isolate b

7=b

Substitute 7 as b into the equation

The line is <u>y=-2x+7</u>

Hope this helps!

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\bold{METHOD\ 1}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\to d=\dfrac{4}{3}e\\\\\text{Substitute it and}\ f=2e\ \text{to the ratio}\ d:e:f:\\\\\dfrac{4}{3}e:e:2e\qquad\text{cancel}\ e\\\\\dfrac{4}{3}:1:2\qquad\text{multiply by 3}\\\\\huge\boxed{4:3:6}

\bold{METHOD\ 2}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\qquad\text{divide both sides by}\ e\neq0\\\\\dfrac{d}{e}=\dfrac{4}{3}\to d:e=4:3\\\\2e=f\qquad\text{divide both sides by 2}\\\\e=\dfrac{f}{2}\to e=\dfrac{1}{2}f\qquad\text{divide both sides by}\ f\neq0\\\\\dfrac{e}{f}=\dfrac{1}{2}\to e:f=1:2\\\\\text{We have}\ d:e=4:3\ \text{and}\ e:f=1:2.

\text{We know}\ \dfrac{1}{2}=\dfrac{1\cdot3}{2\cdot3}=\dfrac{3}{6}\\\\\text{threfore}\ e:f=3:6\\\\\text{Now we have}\\\\\left\begin{array}{ccc}d:e=4:3\\e:f=3:6\end{array}\right\}\large{\boxed{d:e:f=4:3:6}}

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