Answer:
Area= 64pi or 201.06
Circumference: 16pi or 50.265
Step-by-step explanation:
Area= \pi r^{2}
pi (8)^2 = 64pi or 201.06
Circumference= 2pir , 2(pi)8 = 16pi or 50.2
-1/4
This will remain its absolute value
Answer:
-3
Step-by-step explanation:
Numbers that come out of the absolute values are always positive.
|6 - 4| -|3 - 8| =
| 2| - | -5| =
2 - 5 =
-3
Answer:
- <u>Question 1:</u>
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- <u>Question 2:</u>
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- <u>Question 3:</u>
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- <u>Question 4:</u>
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Explanation:
<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>
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a) By definition: 
b) Given: 
c) By substitution: 
<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>
a) <u>Separate variables</u>

b)<u> Integrate</u>


c) <u>Antilogarithm</u>



<u>Question 3. Which particular solution matches the additional information?</u>
<u></u>
Use the measured rate of 4 grams per hour after 3 hours

First, find the mass at t = 3 hours

Now substitute in the general solution of the differential equation, to find A:

Round A to 1 significant figure:
<u>Particular solution:</u>

<u>Question 4. What was the mass of the bacteria at time =0?</u>
Substitute t = 0 in the equation of the particular solution:
