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Artyom0805 [142]
3 years ago
14

Need help with this math problem

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0
Isolate the variable by dividing each side by factors that don't contain the variable.
So it’s D= -5y^2
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Pedro was stocking up on uniforms for the new
Kazeer [188]

Answer

5

Step-by-step explanation:

141.75 - 68 = 73.75

73.75 / 14.75 = 5

8 0
3 years ago
Please help me on this it’s due
olya-2409 [2.1K]
<h3>Answer:  5 cakes</h3>

================================================

Explanation:

Let's start off converting the mixed number 12 & 1/4 to an improper fraction.

a \frac{b}{c} = \frac{a*c+b}{c}\\\\12 \frac{1}{4} = \frac{12*4+1}{4}\\\\12 \frac{1}{4} = \frac{49}{4}\\\\

Do the same for the other mixed number 2 & 1/3.

a \frac{b}{c} = \frac{a*c+b}{c}\\\\2 \frac{1}{3} = \frac{2*3+1}{3}\\\\2 \frac{1}{3} = \frac{7}{3}\\\\

-----------------------

From here, we divide the two fractions. I converted them to improper fractions to make the division process easier.

\frac{49}{4} \div \frac{7}{3} = \frac{49}{4} \times \frac{3}{7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{49\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 7\times 3}{4\times 7}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{7\times 3}{4}\\\\\frac{49}{4} \div \frac{7}{3} = \frac{21}{4}\\\\

The last step is to convert that result to a mixed number.

\frac{21}{4} = \frac{4*5+1}{4}\\\\\frac{21}{4} = \frac{4*5}{4}+\frac{1}{4}\\\\\frac{21}{4} = 4+\frac{1}{4}\\\\\frac{21}{4} = 5 \frac{1}{4}\\\\

Note that 21/4 = 5.25 and 1/4 = 0.25 to help check the answer.

-----------------------

Therefore, she can make 5 cakes. The fractional portion 1/4 is ignored since we're only considering whole cakes rather than partial ones.

3 0
3 years ago
THIS IS NOT A QUIZ!!! Drag the numbers to order them from least to greatest
snow_lady [41]

Answer:

LEAST TO GREATEST

-2.4

-0.8

0.2

0.9

1.6

4 0
3 years ago
Reading a Bar Graph Worksheet
kiruha [24]

Answer:

1. 80 students

2. 45 students

3. i believe that its 25 dollars

4. i dont know sorry

5. i dont know sorry

Step-by-step explanation:

3 0
3 years ago
What is the product? (X^4)(3x^3-2)(4x^2+5x)
Paha777 [63]

Given expression: (x^4)(3x^3-2)(4x^2+5x).

We need to simplify the given expression by multiplying.

\mathrm{Expand}\:\left(3x^3-2\right)\left(4x^2+5x\right):\quad 12x^5+15x^4-8x^2-10x

=\left(x^4\right)\left(12x^5+15x^4-8x^2-10x\right)

\left(x^4\right)\left(12x^5+15x^4-8x^2-10x\right):\quad 12x^9+15x^8-8x^6-10x^5

=12x^9+15x^8-8x^6-10x^5

<h3>Therefore, \left(x^4\right)\left(3x^3-2\right)\left(4x^2+5x\right)=\quad 12x^9+15x^8-8x^6-10x^5..</h3>
6 0
3 years ago
Read 2 more answers
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