<span>4x-y = 15
3x+2y = -8
Multiplying the first equation by two makes for an easy elimination of the y variable.
8x - 2y = 30
3x + 2y = -8
Add vertically.
11x = 22.
Divide by 11 on both sides and get x = 2.
Plug into an equation.
4(2) - y = 15
8 - y = 15
8 = 15 + y
8 - 15 = y
-7 = y.
Thus the solution is indeed (2, -7).</span>
Answer:
228 and 222
Step-by-step explanation:
Quadratic equations are the equations that can be re arranged in the linear or the standard form.
<u>Explanation:</u>
In algebra, a quadratic equation is any condition that can be adjusted in standard structure as where x speaks to an unknown, and a, b, and c speak to known numbers, where a ≠ 0. On the off chance that a = 0, at that point the condition is straight, not quadratic, as there is no term.
Quadratic equations are really utilized in regular day to day existence, as while ascertaining regions, deciding an item's benefit or figuring the speed of an article. Quadratic conditions allude to conditions with in any event one squared variable, with the most standard structure being ax² + bx + c = 0.
Answer:
I think its B
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let's say the number "n" were the largest multiple of 9. But then:
Consider n + 9. n is itself a multiple of 9, so n = 9k, so n + 9 = 9(k + 1), so n + 9 is also a multiple of 9, and n + 9 is larger than n.
So there can't be a largest multiple of 9 (or any number).
