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Katena32 [7]
3 years ago
12

On Earth you weigh 54.5 kilograms, while on the moon you weigh 9,071 grams. How many more grams do you weigh on Earth than on th

e moon?
Mathematics
2 answers:
Nana76 [90]3 years ago
8 0

Answer:

Earth weight:

54.5 kilograms = 54.5 × 10 × 10 × 10 = 54,500 grams

Difference of weights:

54,500 g − 9,071 g = 45,429 grams

Step-by-step explanation:


Sever21 [200]3 years ago
4 0

Answer:

45,429

Step-by-step explanation:

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A right triangle has a base of 11 yards and a height of 7 yards . If you were to construct a similar but not congruent right tri
Dimas [21]

Answer:

bae of 44 yds and a height of 28 yds

Step-by-step explanation:

11x7 = 88 yd^2 = area of small triangle

616/88 = 16 so the larger triangle area is 16 times larger than the smaller triangle.

The area of a triangle is not proportional to it's dimensions. An increase of 16 times the area only increases the dimensions by 4 times.

larger triangle dimensions are 11 x 4 = 44 and 7 x 4 = 28

5 0
3 years ago
Determine the mean of the numbers 6, 17, 22, 28, and 37.
Kipish [7]
To find the mean or the avg you add up all the numbers you have and then divide by how many numbers you added together in this case 5

6+ 17+22+28+37=110

\frac{110}{5} =22

so the mean is 22, hope this helped you!
4 0
3 years ago
Help ya’ll smart people help me
torisob [31]

Answer:

1) -200

2) -126

3) -5 + (-10)

4) -10

5) -60 + (-85) + (-115) = -260

Step-by-step explanation:

You can just add all of them normally then add the negative sign (-) at the end.

Hope this helps!

3 0
3 years ago
Any help if possible Thank you ❤
azamat
I believe it's 37CM, I had that question on my finals last year.
8 0
3 years ago
Read 2 more answers
1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
2 years ago
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