What is the simple intrest on $160 invested at 7% per year for three years

Which statement is true of triangles P and Q? Triangle P has side lengths of 6, 8, 10 and angle measures of 53.1 degrees, 90 deg

Wewaii [24]

Answer:

Triangle P and Triangle Q are mathematically similar shapes (?).

Step-by-step explanation:

Hi, so the question asks which statement is true, given the following information, but you haven't written what statements we can choose from.

After reading the information, we can see that Triangle Q is the same shape as Triangle P but just larger.

I'm assuming that one of the statements given is about Triangle P and Triangle Q being mathematically similar shapes?

If you need to show your working out, here it is:

18 ÷ 6 = 3

24 ÷ 8 = 3

30 ÷ 10 = 3

All the angles are the same.

This means that the length scale factor is +3 from Triangle P to Triangle Q, the area scale factor is +9 (because 3 x 3 = 9) from Triangle P to Triangle Q, and that the two shapes are mathematically similar.

*DISCLAIMER* The majority of question askers on Brainly seem to be from the US, and I'm not, so the way I work things out / the mathematical terms I use might be different. Sorry!

Hope this helped anyway!

Bluey :)

3 0

3 years ago

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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$