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rewona [7]
3 years ago
15

Mario wrote the inequality below to compare two numbers.

Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0

Answer:

58 is greater than 51

Step-by-step explanation:

> is greater than and < is less than

masya89 [10]3 years ago
7 0
58 is greater then 51 58>51
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I need help please and please help
Tamiku [17]

Answer:

whats the question and are you supposed to type in the answer or do they have a choice?

6 0
3 years ago
Can you help me please??
dusya [7]

Answer:

y = \frac{4}{5}x+\frac{54}{5}

Step-by-step explanation:

Equation of a line has been given as,

y=\frac{4}{5}x+\frac{3}{5}

Here, slope of the line = \frac{4}{5}

y-intercept = \frac{3}{5}

"If the two lines are parallel, there slopes will be equal"

By this property slope of the parallel line to the given line will be equal.

Therefore, slope 'm' = \frac{4}{5}

Since, slope intercept form of a line is,

y = mx + b

Therefore, equation of the parallel line will be,

y = \frac{4}{5}x+b

Since, this line passes through a point (-6, 6),

6 = \frac{4}{5}(-6)+b

6 = -\frac{24}{5}+b

b = 6+\frac{24}{5}

b = \frac{30+24}{5}

b = \frac{54}{5}

Equation of the parallel line will be,

y = \frac{4}{5}x+\frac{54}{5}

4 0
3 years ago
A. ASA<br> B. CPCTC<br> C. AAS<br> D. SAS
Ede4ka [16]

Answer:

It is ASA congruence rule as the 2 angles and the included side of the triangle are equal

6 0
3 years ago
Read 2 more answers
Please help me solve. Surface area of this pyramid?
Sever21 [200]

Answer:

4,784ft^2

Step-by-step explanation:

Well in this case we will just use the square and triangle area formulas instead of the pyramid surface area formula.

So if the base is a square then the area is 32*32 which is 1,024.

Now for the trangle, the area of a triangle b*h/2.

So b*h is 47*32 which is 1,504.

So 1,504/2 is 752.

So 752 is the area of 1 triangle and we have 4 so 5*752 is 3,760.

So 3,760 + 1,024 is 4,784.

So the total SA if the pyramid is 4,784ft^3.

6 0
4 years ago
Read 2 more answers
The as x approaches 0 of tan^2x/x
uysha [10]

L=Lim tan(x)^2/x x->0

Since both numerator and denominator evaluate to zero, we could apply l'Hôpital rule by taking derivatives.

d(tan^2(x))/dx=2tan(x).d(tan(x))/dx = 2tan(x)sec^2(x)

d(x)/dx = 1

=>

L=2tan(x)sec^2(x)/1 x->0

= (2(0)/1^2)/1

=0/1

=0


Another way using series,

We know that tan(x) = x+x^3/3+2x^5/15+.....

then tan^2(x), using binomial expansion gives

x^2+2*x^4/3+.... (we only need two terms)

and again apply l'Hôpital's rule, we have

L=d(x^2+2x^4/3+...)/d(x) = (2x+8x^3/3+...)/1

=0 as x->0

3 0
3 years ago
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