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tresset_1 [31]
3 years ago
13

Ben loves Thanksgiving and he cooks the family turkey every year. He has noticed that over the years the amount of people who sh

ow up for his Thanksgiving dinner tends to vary, and he was wondering if this was correlated with the size of the turkeys he cooks. He recorded the weight of the turkeys he cooked (in lbs.) and the amount of guests who showed up for diner for 12 randomly chosen Thanksgivings. When he was analyzing the data he decided to perform a Box Cox transformation and he derived a lambda equal to 0.891.
What transformation does this value of lambda suggest?
a. With a lambda close to 1. it looks like we should take the square root of y
b. With a lambda close to 1. it does not look like we need to re-express the data.
c. With a lambda close to 1, it looks like we should take the log of y
d. With a lambda close to 1. it looks like we should take the log of x.
Mathematics
1 answer:
Anettt [7]3 years ago
4 0

Answer:

The answer is "Option b".

Step-by-step explanation:

Calculating the common Box-Cox Transformation:

\lambda \ value  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Transformed \ data \ (Y')\\\\

  -3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \        Y^{-3} =\frac{1}{Y^3} \\\\     -2  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \     Y^{-2} =\frac{1}{Y^2} \\\\     -1  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \     Y^{-1} =\frac{1}{Y^1} \\\\      -0.5  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \     Y^{-0.5} =\frac{1}{\sqrt{Y}} \\\\      0  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \   \log(Y)^{**} \\\\

    0.5  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \     Y^{-0.5} =\sqrt{(Y)} \\\\         1  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \     Y^{1} =Y \\\\         2  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \     Y^{2} \\\\         3  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \     Y^{3} \\\\

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8 0
3 years ago
SOMEONE HELP PLEASE! ASAP!
Luba_88 [7]
When two lines intersect, the angles across from the intersection (the "X") are congruent (equal), and referred to as "vertical angles."
So by the rule of vertical angles are congruent, we can set them equal:
{x}^{2}  - 6x = 1\div2 \: x + 42 \\  {x}^{2}  - 6x - 1 \div 2 \: x = 42 \\  {x}^{2}  - 6.5x = 42
{x}^{2}  - 6.5x - 42 = 0 \\ multiply \: both\: sides \: by \: 2 \: to \: get \\ rid \: of \: the \: decimal \\ 2({x}^{2}  - 6.5x - 42) = 2(0)
2 {x}^{2}  - 13x - 84 = 0
to factor we need the factors of 84:
1×84, 2×42, 3×28, 4×21, 6×14
Now we need one of those factors ×2 ( from the x^2 term) minus the other factor to equal 13 (the middle term)
it turns out that if we use 4×21: 4×2 = 8
and 21-8 = 13. Woohoo! we got it
So now we have:
2 {x}^{2}  - 13x - 84 = 0 \\ (2x - 21)(x + 4) = 0
Now set each factor = 0
1) 2x - 21 = 0 and 2) x + 4 = 0
1) 2x - 21 = 0, 2x = 21, x = 21/2 = 10.5
2) x + 4 = 0, x = -4

Now we plug in each answer to check:
1) x = 10.5
{x}^{2}  - 6x =  {(10.5)}^{2}  - 6(10.5) \\  = 110.25 - 63 = 47.25
1/2x + 42 = 1/2(10.5) + 42 = 5.25 + 42 = 47.25
47.25 = 47.25
BAM SO IT LOOKS LIKE THAT'S IT!!
But let's check 2) first:
2) x = -4
{( - 4)}^{2}  - 6( - 4) = 16 + 24 = 40
1/2x + 42 = 1/2(-4) + 42 = -2 + 42 = 40
40 = 40, so both work!!
But it asks for m<1, and <1 is supplementary because it lies on same line, meaning the sum of both = 189
Therefore m<1 = 180 - 47.25 = 132.75°
OR m<1 = 180 - 40 = 140°


6 0
3 years ago
Guyssssssss help me 10 points!!
zlopas [31]

Answer:

19

Step-by-step explanation:

the side is same as 57

what times 3 is 57?

57/3 is 19

AB is 19

pls vote me as brainliest!!!<3

8 0
3 years ago
A rectangle has an area of 96 in2. The rectangle's base is 4 in. What is the height of the rectangle?
gavmur [86]
96/4=24in, so B
Hope this helps :)
6 0
3 years ago
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