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svetlana [45]
3 years ago
15

What is the solution 1/2x=5/6

Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0
Solve:
☃Multiply 2 on both sides of the equation.
☃Solve
X=5/3
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Stacey wishes to make a hamburger which is lower in fat without having to give up the great taste. She purchases 5 pounds of gro
STALIN [3.7K]

Answer:

%P = 8%

the percentage of fat in the mixture is 8%

Step-by-step explanation:

Given;

The percentage of fat in the mixture is;

%P = total mass of fat in mixture/total mass of mixture × 100%

%P = F/T × 100% ….....1

Mass of fat in mixture is;

She purchases 5 pounds of ground beef which is 15% fat

F1 = 15% of 5 pounds = 0.15×5 pounds

F1 = 0.75 pound

and combines it with 7 pounds of ground turkey which is only 3% fat

F2 = 3% of 7 pounds = 0.03 × 7

F2 = 0.21 pound

Total mass F = F1 + F2

F = 0.75+0.21

F = 0.96 pound

Total mass of mixture T = 5 + 7 pounds

T = 12 pounds.

From equation 1,

%P = F/T × 100%

%P = 0.96/12 × 100%

%P = 0.08×100%

%P = 8%

the percentage of fat in the mixture is 8%

5 0
3 years ago
How do I solve 3x(4x-15)
inna [77]
3x(4x - 15) < Given
12x^2 - 45x < Distributive law of property

By the way, you are simplifying not solving. You solve equations and simplify expressions.

7 0
3 years ago
A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple
tester [92]

Answer:  The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation:  We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.

Therefore, the probability of event A is given by

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0
2 years ago
Help me need correct rn ASAP
Svetach [21]

Answer:

y=\frac{3}{2}x+3

Step-by-step explanation:

6 0
3 years ago
CAN YOU SOLVE THIS MATH PROBLEM 20 POINTS
Zolol [24]
The correct answer is A. x=22

Since the angles of a rectangle are right angles (90 degrees) you would set it up as 90=5x-20. Then combine like terms and solve the equation. (If you need me to show you how step by step tell me)
7 0
2 years ago
Read 2 more answers
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