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amm1812
3 years ago
15

How do i solve the proportion 4/9=10/x

Mathematics
1 answer:
lapo4ka [179]3 years ago
8 0

Answer:

x=45/2

Step-by-step explanation:

4/9=10/x

cross product

9*10=4*x

90=4x

x=90/4

simplify

x=45/2

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Solve. the square root of 44-2x = x-10
Anuta_ua [19.1K]
44-2x=x-10 subtract 44 from both sides -2x= x-54 subtract x from both sides -3x= -54 divide by -3 x= 18 square root of 18= 4.24 in radical form 3 square root of 2 hope this helps
5 0
3 years ago
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0

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9^2 * (1/3)^2 -9

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3 years ago
If a 40-m rope is cut into two pieces in the ratio 3:5 how long is each piece
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6 0
3 years ago
The area of the shaded segment is 100cm^2. Calculate the value of r.
Reil [10]
Hello, 

The formula for finding the area of a circular region is: A=  \frac{ \alpha *r^{2} }{2}

then:
A_{1} = \frac{80*r^{2} }{2}

With the two radius it is formed an isosceles triangle, so, we must obtain its area, but first we obtain the height and the base.

cos(40)= \frac{h}{r}  \\  \\ h= r*cos(40)\\ \\ \\ sen(40)= \frac{b}{r} \\ \\ b=r*sen(40)

Now we can find its area:
A_{2}=2* \frac{b*h}{2}  \\  \\ A_{2}= [r*sen(40)][r*cos(40)]\\  \\A_{2}= r^{2}*sen(40)*cos(40)

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Answer: r= 1.59cm
7 0
2 years ago
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