2.85 × 10^22. A diamond with a mass of 0.568 g contains
2.85 × 10^22 atoms C.
Diamond is a form of pure carbon.
a) Convert <em>grams of C to moles of C</em>
Moles of C = 0.568 g C × (1 mol C/12.01 g C) = 0.047 29 mol C
b) Convert <em>moles of C to atoms of C
</em>
Atoms of C = 0.047 29 mol C × (6.022 × 10^23 atoms C)/(1 mol C)
= 2.85 × 10^22 atoms C
Answer: Sodium (Na – Natrium)
Potassium (K – Kalium)
Answer : The heat energy absorbed will be, 
Solution :
The process involved in this problem are :
The expression used will be:
![\Delta H=m\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]](https://tex.z-dn.net/?f=%5CDelta%20H%3Dm%5Ctimes%20%5CDelta%20H_%7Bfusion%7D%2B%5Bm%5Ctimes%20c_%7Bp%2Cl%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D)
where,
m = mass of ice = 1100 g
= specific heat of liquid water = 
= enthalpy change for fusion = 
Molar mass of water = 18 g/mole
Now put all the given values in the above expression, we get:
![\Delta H=1100g\times 333.89J/g+[1100g\times 4.18J/g^oC\times (32.0-0)^oC]](https://tex.z-dn.net/?f=%5CDelta%20H%3D1100g%5Ctimes%20333.89J%2Fg%2B%5B1100g%5Ctimes%204.18J%2Fg%5EoC%5Ctimes%20%2832.0-0%29%5EoC%5D)
Conversion used : (1 cal = 4.184 J)
Therefore, the heat energy absorbed will be,
Answer: 0.0826mol
PV=nRT
n=PV/RT
n=(1atm)(2.1L)/(310K)(0.082057L*atm/mol*K)=0.0826mol
