The ZnCl₂ solution have a molarity of 1.33 M.
Explanation:
We have the following chemical reaction:
Zn (s) + CuCl₂ (aq) → ZnCl₂ (aq) + Cu (s)
number of moles = mass / molar weight
number of moles of Zn = 25 / 65.4 = 0.38 moles
From the chemical equation we see that 1 moles of Zn produces 1 mole of ZnCl₂, so 0.38 moles of Zn will produce 0.38 moles of ZnCl₂.
molarity = number of moles / volume (L)
molarity of the ZnCl₂ solution = 0.38 / 0.285 = 1.33 M
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2C2H2(l) +5O2(g)→ 4Co2(g) + 2H2O
The limiting reactant for reaction above is O2
<u><em>explanation</em></u>
The limiting reagent is determined using mole ratio of both reactant.
that is the mole ratio of C2H2:O2 which is 2:5 .
The mole ratio above implies that 37.0 mole of C2H2 needs 37.0 moles x5/2=92 moles of O2.
<em>Since the available moles of O2 was 81.0 mole and 92 moles are required to completely react with C2H2</em><em> ,</em> <u>O2 is the limiting reagent.</u>