There are four nitrogenous bases that makes DNA. These are A, T, G and C. If a DNA strand has eight pairs of nitrogenous bases, the eight bases can be
1. AA GG TT CC
2. GC GG AT CG
3. AT TA GG GC
4. GA AG GC GG
Like this, there can be 65,536 different sequences with ATCG.
Since we have 4 nitrogenous bases, pairing will make 4 X 4 = 16 combinations. If we have to make 8 pairs of bases, the number of possible sequences would be 4 to the power 8.
Answer: THERE WILL BE 65,536 DIFFERENT SEQUENCES OF 8 BASES.
Answer: C.
Explanation:
Out of all of the answer choices, answer C most properly describes the cell cycle.
