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bonufazy [111]
3 years ago
10

SOME PLEASE HELP ME WITH THIS ITS DUO TODAY​

Mathematics
1 answer:
Svet_ta [14]3 years ago
3 0

Answer:

Blank above the 3: 9

Blanks underneath the 593: 540

Blanks underneath the line: 53

Blank by the "R": 53

Step-by-step explanation:

Simply divide.

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Look at the system of equations below. Y=2x+5 y=x+6 What is the x-coordinate of the solution to the system?
soldi70 [24.7K]

Answer:

1

Step-by-step explanation:

Given the system of equations below

y=2x+5

y=x+6

Equating the right hand side of the expressions we will have;

2x+5 = x+6

Collect the like terms;

2x - x = 6 - 5

x = 1

Hence the x-coordinate of the solution to the system is 1

4 0
3 years ago
37/8 as a mixed number
Alexxandr [17]
4 5/8
you see how many time 8 goes into 37 which is 4 and then you have 5 left over
8 0
3 years ago
During the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this
alex41 [277]

Answer:

Step-by-step explanation:

Given that during  the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this period, P(t) remained close to the solution of the initial value problem.

\frac{dP}{dt} =0.03135P =0.0001489P^2, P(0) = 3.9

a) 1930 population is the population at time t = 40 years taking base year as 40

We can solve the differential equation using separation of variables

\frac{dP}{0.03135P – 0.0001489P^2 } =dt\\\frac{dP}{-P(0.03135 – 0.0001489P } =dt

Resolve into partial fractions

\frac{31.8979}{P} -\frac{0.00474}{0.0001489P-0.03135}

Integrate to get

ln P -0.00474/0.0001489  (ln (0.0001489P-0.03135) = t+C

ln P -31.833  (ln (0.0001489P-0.03135) =t+C

\frac{P}{( ( (0.0001489P-0.03135)^{31.833}  } =Ae^t

Limiting population would be infinity.

6 0
3 years ago
Pls HELP, WILL GAVE A 5 STAR RATING AND BRAINLIEST
bonufazy [111]

Answer:

Step-by-step explanation:

-7x-3=2-7x-5

cancel equal terms

-3=2-5

calculate the difference

-3= -3

This statement is true.

6 0
3 years ago
What in math what does it mean when I'd a sample process is in control or not?
Aleks04 [339]
I'm not totally sure what you are asking, but maybe this is a question about dependent and independent variables?

If so, these types of variables are used in math and science as measures. In math, independent variables and dependent variables are the "tools" used in an experiment. 

Independent variables are the variables that are controlled during the experiment. These variables do not change during the experiment.

Dependent variables are the variables whose values change based on the independent variables. These variables are the "outcome" portion. 


I have no idea if this answers your question or not. All I can say is that the "controlled" part of a sample would be the independent variable. 
8 0
3 years ago
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