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Morgarella [4.7K]
3 years ago
7

What which relationship in each of the following represents a Non-proportional relationship

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0
The answer is C y =3.5x
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2 years ago
Here are Babe Ruth's home run totals for the New York Yankees during the years 1920 - 1934:54, 59, 35, 41, 46, 25, 47, 60, 54, 4
Irina-Kira [14]

Given data is 54, 59, 35, 41, 46, 25, 47, 60, 54, 46, 49, 46, 41, 34, 22

Arranging it in increasing order:

22 25 34 35 41 41 46 46 46 47 49 54 54 59 60

Number of data items, n=15.

Finding Median, First Quartile, and Third Quartile

Finding\;\;median\\M=\frac{n+1}{2}th\;\;term =\frac{15+1}{2}=8th\;\;term\;\; i.e. \;\;46

22 25 34 35 41 41 46 46 46 47 49 54 54 59 60

Now finding First Quartile from set: 22 25 34 35 41 41 46

Q₁ = middle term i.e. 35

Now finding Third Quartile from set: 46 47 49 54 54 59 60

Q₃ = middle term i.e. 54

So we have Q₁ = 35, M = 46, and Q₃ = 54. Lower bound is 22 and Upper bound is 60.

While drawing the given data on number line and marking First quartile, Median, Third quartile on number line. We can clearly observe that option A matches with given data points.

Hence, option A i.e. Box-plot A is the correct choice.

5 0
3 years ago
Read 2 more answers
Two BLARBs equal one BLABB. Three BLABBs equal ten BLALBs, and one BLALB equals two BABs. How many BABs equal 6 BLARBs?
puteri [66]
6 barbs =22  as your answer
8 0
3 years ago
Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).
Vanyuwa [196]
L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\\\\(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\\\\(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\\\\(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\\\\(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\\\dots-3c^4a^2+3c^2a^4-a^6\\\\=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)

R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\\\\=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\\\\=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\\\\=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\\\\L=R
5 0
2 years ago
Read 2 more answers
Can someone help me?
OverLord2011 [107]
With what do you need help
6 0
3 years ago
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