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Morgarella [4.7K]
3 years ago
7

What which relationship in each of the following represents a Non-proportional relationship

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0
The answer is C y =3.5x
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There are four students and a lecturer for a photography session. Determine the number of ways the people can be arranged such t
steposvetlana [31]

Answer:

24 ways

Step-by-step explanation:

Given that

Number of students = 4

Lecturer have to stand in the middle position.

We have five places in which middle place is for lecturer,now we have four places and we have to arrange four students on that four places.So there will 4! ways to arrange those students.

4!= 4 x 3 x 2 x 1

4! =24

So we have 24 ways to arrange 4 students and one lecturer .

5 0
3 years ago
Find an equation for the line perpendicular to 4x+12y=72 and goes through the point (-9,6)
il63 [147K]

Answer:

Step-by-step explanation:

Given the equation

4x+12y=72

The equation of a line can written as

y=mx+c

Where m is the slope

And c is the intercept on y axis

Then, we need to write the equation given in the form of equation of a line (y=mx+c), by making y subject of the formula

4x+12y=72

12y=-4x+72

Divide through by 12

y=-4x/12 + 72/12

y=-⅓x+6

Then, comparing with equation of a line shows that

m=-⅓ and c=6

So we need to get another linen that is perpendicular to this line and passes through the point (-9,6)

The slope of the line perpendicular to another line is given as

m1=-1/m2

Then, m1=-1÷-⅓

Then, the slope of the perpendicular line is 3

Then, m=3

So apply this to equation of the line

y=mx+c

Then, y=3x+c

So to know c, we will insert the point given(-9,6), x=-9 and y=6

y=3x+c

6=3(-9)+c

6=-27+c

Then, c=6+27

c=33

Then, the equation of line becomes

y=3x+33

7 0
3 years ago
7. Maria quiere agrandar la foto de su
lukranit [14]

Answer:

the perimeter is 960

Step-by-step explanation:

The computation of the perimeter is shown below;

If we assume

= (24 × 2) + (6 × 2)

= 48 + 12

= 60

And, the area is 16 times to that of original So

= 60 × 16

Hence, the perimeter is 960

7 0
3 years ago
Which Pairs are additive inverses?<br> a. 6,-(-6)<br> b. -7,7<br> c.-7,-7<br> d.7,7<br> e.6,-6
xz_007 [3.2K]

I was never sure of what the "additive inverse" is. 
So, just now, just for you, I went and looked it up.

The additive inverse of any number ' A ' is the number
that you need to ADD to A to get zero.  That's all !

So now, let's check out the choices:

a), 6, -(-6)

That second number, -(-6), is the same as +6 .
So the two numbers are the same.
Do you get zero when you add them up ?  No.

b). -7, 7
What do you get when you add -7 and 7 ?
You get zero.
So these ARE additive inverses.

c). -7, -7
What do you get when you add -7 to -7 ?
You get -14 .  That's not zero, so these
are NOT additive inverses.

d).  7, 7
What do you get when you add 7 to 7 ?
You get 14.  That's NOT zero, so these
are NOT additive inverses.

e).  6, -6
What do you get when you add 6 to -6 ?
You get zero.
So these ARE additive inverses.

What do we end up with from the list of choices:

a).,  c).,  and d). are NOT additive inverses.

b). and e). ARE additive inverses.

7 0
3 years ago
Read 2 more answers
Which of the following is an asymptote of y = sec(x)?
babunello [35]
Answer: option d. x = 3π/2

Solution:

function y = sec(x)

1) y = 1 / cos(x)

2) When cos(x) = 0, 1 / cos(x) is not defined

3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...

4) limit of sec(x) = lim of 1 / cos(x).

When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.

So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).

Answer: 3π/2

The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).

8 0
3 years ago
Read 2 more answers
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