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ExtremeBDS [4]
3 years ago
15

It says use cofunction but still i didnt understand

Mathematics
1 answer:
torisob [31]3 years ago
5 0

Answer:

-\frac{\pi }{22\\}

Step-by-step explanation:

\frac{5\pi }{11}-pi/2

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A map of a public park shows a circular pond. There is a bridge along a diameter of the pond that is 0.25 mi long. You walk acro
Valentin [98]

The distance further the friend walked is 0.41 miles.

<h3>How much farther did the friend walk?</h3>

The distance the friend walked can be determined by calculating the circumference of a semicircle.

Circumference of a semicircle = πr + 2r

r = 0.25 / 2 = 0.125mi

3.14 x 0.125 + 0.25 = 0.66 mi

Difference in the distance = 0.66 - 0.25 = 0.41 miles

To learn more about how to determine the circumference, please check: brainly.com/question/14351152

##SPJ1

7 0
2 years ago
If the equatorial diameter of the sun is 1.39 million km how many kilometers is the sun's radius
son4ous [18]
Since the radius of an object is half of the diameter, your equation and answer would be: 1.39 million divided by 2 = 695,000 km.
6 0
3 years ago
The value pi/4 is a solution for the equation 3 sqrt 2 cos theta+2=-1
natulia [17]

Answer:

<h2>FALSE</h2>

Step-by-step explanation:

3\sqrt2\cos\theta+2=-1\\\\\text{Method 1}\\\\\text{Put}\ \theta=\dfrac{\pi}{4}\ \text{to the equation and check the equality:}\\\\\cos\dfrac{\pi}{4}=\dfrac{\sqrt2}{2}\\\\L_s=3\sqrt2\cos\dfrac{\pi}{4}+2=3\sqrt2\left(\dfrac{\sqrt2}{2}\right)+2=\dfrac{(3\sqrt2)(\sqrt2)}{2}+2\\\\=\dfrac{(3)(2)}{2}+2=3+2=5\\\\R_s=-1\\\\L_s\neq R_s\\\\\boxed{FALSE}

\text{Method 2}\\\\\text{Solve the equation:}\\\\3\sqrt2\cos\theta+2=-1\qquad\text{subtract 2 from both sides}\\\\3\sqrt2\cos\theta=-3\qquad\text{divide both sides by}\ 3\sqrt2\\\\\cos\theta=-\dfrac{3}{3\sqrt2}\\\\\cos\theta=-\dfrac{1}{\sqrt2}\cdot\dfrac{\sqrt2}{\sqrt2}\\\\\cos\theta=-\dfrac{\sqrt2}{2}\to\theta=\dfrac{3\pi}{4}+2k\pi\ \vee\ \theta=-\dfrac{3\pi}{4}+2k\pi\ \text{for}\ k\in\mathbb{Z}\\\\\text{It's not equal to}\ \dfrac{\pi}{4}\ \text{for any value of }\ k.

7 0
3 years ago
What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?
Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

Solution:  

x-6y=42    ..................Given

which can be written as

y=mx+c

Where m is the slope of the line

∴ y=\dfrac{x}{6}-7

On Comparing we get

Slope = m = \dfrac{1}{6}

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

(y-y_{1})=m(x-x_{1})

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

3 0
3 years ago
The area of a square is
harkovskaia [24]

square has 4 equal sides

so A = 144 =  12^2

A = L x W

= W. W

= W^2

12^2 = W^2

so W = 12

answer: one side of the square = 12

   

7 0
3 years ago
Read 2 more answers
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