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ExtremeBDS [4]
3 years ago
15

It says use cofunction but still i didnt understand

Mathematics
1 answer:
torisob [31]3 years ago
5 0

Answer:

-\frac{\pi }{22\\}

Step-by-step explanation:

\frac{5\pi }{11}-pi/2

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PLEASE HELP simple geometry problem
vlabodo [156]

Perimeter is adding the 3 sides together. Since both triangles have the same perimeter set both triangles to equal:


(x+3 + x+3 + x+3) = (x+3 + 2x-3 + x)

Simplify each side:

3x+9 = 4x

Subtract 3x from each side:

x=9



5 0
4 years ago
Check my answers? questions in the attachment :)
GarryVolchara [31]
1 Correct!
2 Correct!
3 Correct!
4 Correct!
5 Correct!



6 0
4 years ago
suppose that y varies inversely with x, and y=3 when x=5. what is an equation for the inverse variation
Angelina_Jolie [31]
The inverse variation of y=3 would be y=1/3
The inverse variation of x=5 would be x=1/5

You just need to flip the variation around.

Your answer is: y=1/3; x=1/5 

Have an amazing day and stay hopeful!

7 0
3 years ago
- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of t
vladimir2022 [97]

EXPLANATION

Given the function f(x) = (x-6)^2 + 1

\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

=x^2-12x+37\mathrm{The\: parabola\: params\: are\colon}a=1,\: b=-12,\: c=37x_v=-\frac{b}{2a}x_v=-\frac{\left(-12\right)}{2\cdot\:1}\mathrm{Simplify}x_v=6y_v=6^2-12\cdot\: 6+37

Simplify:

y_v=1

\mathrm{Therefore\: the\: parabola\: vertex\: is}\mleft(6,\: 1\mright)\mathrm{If}\: a\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}a=1\mathrm{Minimum}\mleft(6,\: 1\mright)\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

y=x^2-12x+37\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}a=1,\: b=-12x=\frac{-\left(-12\right)}{2\cdot\:1}\mathrm{Refine}

Axis of simmetry : x=6

The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.

3 0
1 year ago
Which ordered pair needs needs to be removed in order for the mapping to represent a function?
Fed [463]

Answer:

b - (-2,-1)

Step-by-step explanation:

A function is a mapping in which each element of the domain, or input, is mapped to one element of the range, or output.

In this mapping, the input value -2 is mapped to both 2 and -1; this makes the points (-2, 2) and (-2, -1).  If one of these two was removed, the mapping becomes a function.

The only one of these listed in the values given is (-2, -1).

4 0
3 years ago
Read 2 more answers
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