Please help! 16/20. Will give brainliest! Spam answers will not be tolerated!

Sebastian and his family picked 4 1/4 bushels of red apples and 2 5/6 of green apples at the orchard. How many more red apples w

11111nata11111 [884]

Answer:

1 5/12

Step-by-step explanation:

4 1/4- 2 5/6= 1 5/12

Also 1 5/12+ 2 5/6= 4 1/4

8 0

3 years ago

A polyhedron with two parallel congruent faces called bases connected by parallelogram faces is called a...

lisov135 [29]

Answer:

right prism

Step-by-step explanation:

If the faces are rectangles, then this prism is called a "right prism"

4 0

3 years ago

Dale deposits $4000 into an account that pays simple interest at a rate of 6% per year. How much interest will he be paid in the

BartSMP [9]

Answer:

$1200

Step-by-step explanation:

$4000 x .06 = $240 x 5 years = $1200

7 0

3 years ago

The Eco Pulse survey from the marketing communications firm Shelton Group asked individuals to indicate things they do that make

Bad White [126]

Answer:

a) There is a probability of 42% that the person will feel guilty for only one of those things.

b)There is a probability of 46% that a randomly selected person will not feel guilty for either of these reasons

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, for those people that will feel guilty about wasting food.

-Set B, for those people that will feel guilty about leaving lights on when not in a room.

The most important information is that there is a .12 probability that a randomly selected person will feel guilty for both of these reasons. It means that $P(A \cap B) = .12.$

The problem also states that there is a .39 probability that a randomly selected person will feel guilty about wasting food. It means that P(A) = 0.39. The probability of a person feeling guilty for only wasting food is PO(A) = .39-.12 = .27.

Also, there is a .27 probability that a randomly selected person will feel guilty about leaving lights on when not in a room. So, the probability of a person feeling guilty for only leaving the lights on is PO(B) = 0.27-0.12 = 0.15.

a) What is the probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room?

This is the probability that the person feels guilt for only one of those things, so:

P = PO(A) + PO(B) = 0.27 + 0.15 = 0.42 = 42%

b) What is the probability that a randomly selected person will not feel guilty for either of these reasons

The sum of all the probabilities is always 1. In this problem, we have the following probabilies

- The person will not feel guilty for either of these reasons: P

- The person will feel guilty for only one of those things: PO(A) + PO(B) = 0.42

- The person will feel guilty for both reasons: PB = 0.12

So

`P + 0.42 + 0.12 = 1

P = 1-0.54

P = 0.46