Trying to factor by splitting the middle term
Factoring <span> b2-4b+4</span>
The first term is, <span> <span>b2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> -4b </span> its coefficient is <span> -4 </span>.
The last term, "the constant", is <span> +4 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> 1 • 4 = 4</span>
Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is <span> -4 </span>.
<span><span> </span></span>
<span><span>-4 + -1 = -5</span><span> -2 + -2 = -4 That's it</span></span>
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and -2
<span>b2 - 2b</span> - 2b - 4
Step-4 : Add up the first 2 terms, pulling out like factors :
b • (b-2)
Add up the last 2 terms, pulling out common factors :
2 • (b-2)
Step-5 : Add up the four terms of step 4 :
(b-2) • (b-2)
Which is the desired factorization
Answer:
v = -8
Step-by-step explanation:
2 + v/2 = -2
Subtract 2 from each side
2-2 + v/2 = -2-2
v/2 =-4
Multiply each side by 2
v/2*2 = -4*2
v = -8
<span><span><span><span><span><span>x</span><span>=</span><span>2</span><span>(</span><span>y</span><span>+</span><span>3</span><span>)</span></span></span></span></span></span><span>x=<span><span>9</span><span><span>2(y−37)</span></span><span></span>
</span></span><span><span>
</span></span>
7(x + 2) = 6(x + 5)
7x + 14 = 6x + 30 |subtract 14 from both sides
7x = 6x + 16 |subtract 6x from both sides
x = 16
Answer:
5+4+7
Step-by-step explanation:
I think
